Question 2 (a) A B 79 volts 9 ohms 5 ohms 1 ohm 2 ohms 79 volts F E D Applying Kirchhoff's current law to junction B or junction E gives I, = 1, +1,. Applying Kirchhoff's voltage law to the closed path ABEFA yields 17, +2/, +51, = 79. Similarly, applying Kirchhoff's voltage law to the closed path BCDEB, we obtain |(-1,) +91, =79 . Determine the currents (I1, I, and Is) of the above electrical circuit by using Gauss Jordan elimination. (b) Find the deteminant of the following matrix using the properties of deteminant. 6 -9 8 5 3 2 -10 -1 11 -7 -4 12 -6 -3 -5 -13 10 -12 -8 -11 -2 7

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