-가 Question-2 a) Find the derivative of f(x) = 2x? –- at x = 3 using definition of derivative at a point. (6+ 2x, 0 < x < 3 x = 3 b) If the function g(x) = }a, (kx, is continuous, then find the 3 < x< 6 value of k and a. Oueg
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- 5,6 use derivative rules to find f1(x)Describe the two methods that help to differentiate the equations implicitly, and find the derivative? Explain with examples?Find the derivative of f(x) = -5x-6. Do not include "f'(x) = " in your answer. For example, if your answer is f'(x) = x2, you would enter x2.
- evaluate the derivative of the function at the given pointf(x)=-4/(2x2-3x)4 , (1,-4)Please don't format the response like this: Now find the derivative of the given function. h'x=dhxdx=ddxtan2x+5=sec22x+5·ddx2x+5 Apply the Chain rule=sec22x+5ddx2x+ddx5=sec22x+52·ddxx+5·ddx1=sec22x+521x1-1+50 Apply the Power law=sec22x+521+0=sec22x+52=2sec22x+5 Now find the second derivative of the given function. h''x=d2hxdx2=ddxdhxdx=ddx2sec22x+5=2·ddxsec22x+5=2ddxsec2x+52=22sec2x+52-1·ddxsec2x+5 Apply the Chain rule=22sec2x+51sec2x+5tan2x+5·ddx2x+5 Again apply the Chain rule=22sec22x+5tan2x+5ddx2x+ddx5=22sec22x+5tan2x+52ddxx+5ddx1=22sec22x+5tan2x+521x1-1+50 Apply the Power law=22sec22x+5tan2x+52=8sec22x+5tan2x+5 Therefore, h'x=2sec2(2x+5)h''x=8sec2(2x+5)tan(2x+5) It is difficult to read when I don't understand the problem and want to learnFind the derivative of h(x)=(-2x-5)3 (2x-4)5you should leave your answer in factored form. Do not include "h′(x)=" in your answer.