Question 2The man is pushing the dresser (ofuniform weight) across a laminatesurface. The dresser has a weight of 80Ib, and the coefficient of friction, µs =0.25. If the man pushes in the direction302mshown.a) Determine the smallest force Fnecessary to slide the dresser.(slipping).1.5mFs=2701b6b) Determine the smallest F necessary to tip the dresser.F;= 267.5 bbc) Which way will the dresser move first?d) The man has a weight of 150 lb. given the answer to part a and b, determine the minimumcoefficient of friction between the man's shoes and the floor so that he doesn't slip.Mg= 0.171

Answered: Image /qna-images/answer/d3ced172-8799-4a1f-9ad3-79402997ddc6.jpg

Question 2 The man is pushing the dresser (of uniform weight) across a laminate surface. The dresser has a weight of 80 Ib, and the coefficient of friction, µ, = 0.25. If the man pushes in the direction 30 2m shown. a) Determine the smallest force F 1.5m necessary to slide the dresser. (slipping). Fs=22016 b) Determine the smallest F necessary to tip the dresser. F;= 267.5 Hb c) Which way will the dresser move first? d) The man has a weight of 150 lb. given the answer to part a and b, determine the minimum coefficient of friction between the man's shoes and the floor so that he doesn't slip. Ms= 0.17}

Question 2 The man is pushing the dresser (of uniform weight) across a laminate surface. The dresser has a weight of 80 Ib, and the coefficient of friction, µ, = 0.25. If the man pushes in the direction 30 2m shown. a) Determine the smallest force F 1.5m necessary to slide the dresser. (slipping). Fs=22016 b) Determine the smallest F necessary to tip the dresser. F;= 267.5 Hb c) Which way will the dresser move first? d) The man has a weight of 150 lb. given the answer to part a and b, determine the minimum coefficient of friction between the man's shoes and the floor so that he doesn't slip. Ms= 0.17}

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter7: Dry Friction

Section: Chapter Questions

Problem 7.73P: The normal pressure acting on the disk of the sander is given by p=(4/3)+(r2/6), where p is the...

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