Question 3. A three-phase impedance load balanced D a connected load in parallel with a balanced ? connected loadmade of bonding. D each arm for the load ?D = 6 + 6? and ? each arm for the connected loadIt is given as ?? = 2 + 2?. ? the connected load ?? = 1? is earthed through the neutral impedance.To this impedance load, the symmetrical component voltages ?0 = 10∠60°, ?1 = 100∠0° and ?2 =Unbalanced phase-to-earth voltages ??, ?? and ?? of 15∠200° volts were applied.a) Draw the zero, positive and negative sequence circuits.b) Find the complex powers imparted to each component circuit. Question 3. A three-phase impedance load balanced A a connectedload in parallel with a balanced y connected loadmade of bonding. A each arm for the load ZA = 6 + 6j and y each armfor the connected loadIt is given as ZY=2+2j. Y the connected load Zn = 1j is earthedthrough the neutral impedance.To this impedance load, the symmetrical component voltages v0 =10z60°, v1 = 100z0° and v2 =Unbalanced phase-to-earth voltages Va, Vb and Vc of 152200° voltswere applied.a) Draw the zero, positive and negative sequence circuits.b) Find the complex powers imparted to each component circuit.

Given,Impedances,Z∆=6+6j Ω.ZY=2+2j Ω.Zn=1j Ω.Voltages,V0=10∠60° V.V1=100∠0° V.V2=15∠200° V.

Question 3. A three-phase impedance load balanced A a connected load in parallel with a balanced y connected load made of bonding. A each arm for the load ZA = 6 + 6j and y each arm for the connected load It is given as ZY = 2 + 2j. Y the connected load Zn = 1j is earthed through the neutral impedance. To this impedance load, the symmetrical component voltages vo 10z60°, v1 = 100z0° and v2 = Unbalanced phase-to-earth voltages Va, Vb and Vc of 152200° volts were applied. a) Draw the zero, positive and negative sequence circuits,

Question 3. A three-phase impedance load balanced A a connected load in parallel with a balanced y connected load made of bonding. A each arm for the load ZA = 6 + 6j and y each arm for the connected load It is given as ZY = 2 + 2j. Y the connected load Zn = 1j is earthed through the neutral impedance. To this impedance load, the symmetrical component voltages vo 10z60°, v1 = 100z0° and v2 = Unbalanced phase-to-earth voltages Va, Vb and Vc of 152200° volts were applied. a) Draw the zero, positive and negative sequence circuits,

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter8: Symmetrical Components

Section: Chapter Questions

Problem 8.46P

See similar textbooks

Similar questions

One advantage of balanced three-phase systems over separate singlephase systems is reduced capital and operating costs of transmission and distribution. (a) True (b) False
It is stated that (i) balanced three-phase circuits can be solved in per unit on a per-phase basis after converting - load impedances to equivalent Y impedances. (ii) Base values can be selected either on a per-phase basis or on a three-phase basis. (a) Both statements are true. (b) Neither is true. (c) Only one of the above is true.
A balanced -connected impedance load with (12+j9) per phase is supplied by a balanced three-phase 60-Hz,208-V source, (a) Calculate the line current, the total real and reactive power absorbed by the load, the load power factor, and the apparent load power, (b) Sketch a phasor diagram showing the line currents, the line-to-line source voltages, and the -load currents. Use Vab as the reference.
Figure 3.32 shows the oneline diagram of a three-phase power system. By selecting a common base of 100 MVA and 22 kV on the generator side, draw an impedance diagram showing all impedances including the load impedance in per-unit. The data are given a follows: G:90MVA22kVx=0.18perunitT1:50MVA22/220kVx=0.10perunitT2:40MVA220/11kVx=0.06perunitT3:40MVA22/110kVx=0.064perunitT4:40MVA110/11kVx=0.08perunitM:66.5MVA10.45kVx=0.185perunit Lines I and 2 have series reactances of 48.4 and 65.43, respectively. At bus 4, the three-phase load absorbs 57 MVA at 10.45 kV and 0.6 power factor lagging.
A balanced three-phase load is connected to a 4.16-kV, three-phase, fourwire, grounded-wye dedicated distribution feeder. The load can be mode led by an impedance of ZL=(4.7+j9)/phase, wye-connected. The impedance of the phase conductors is (0.3+j1). Determine the following by using the phase A to neutral voltage as a reference and assume positive phase sequence: (a) Line currents for phases A, B, and C. (b) Line-to-neutral voltages for all three phases at the load. (c) Apparent. active, and reactive power dissipated per phase, and for all three phases in the load. (d) Active power losses per phase and for all three phases in the phase conductors.
The three-phase source line-to-neutral voltages are given by Ean=100,Ebh=10+240, and Ecn=10240volts. Is the source balanced? (a) Yes (b) No
In a balanced three-phase Y-connected system with a positive-sequence source, the line-to-line voltages are 3 times the line-to-neutral voltages and lend by 30. (a) True (b) False
For a balanced- load supplied by a balanced positive-sequence source. the line currents into the load are 3 times the -Ioad currents and lag by 30. (a) True (b) False
Two balanced Y-connected loads, one drawing 10 kW at 0.8 power factor lagging and the other IS kW at 0.9 power factor leading, are connected in parallel and supplied by a balanced three-phase Y-connected, 480-V source. (a) Determine the source current. (b) If the load neutrals are connected to the source neutral by a zero-ohm neutral wire through an ammeter, what will the ammeter read?
A single-phase source is applied to a two-terminal, passive circuit with equivalent impedance Z=3.045, measured from the terminals. The source current is i(t)=22cos(t)kA. Determine the (a) instantaneous power, (b) real power, (c) reactive power delivered by the source, and (d) source power factor.
Two balanced three-phase loads that are connected in parallel are fed by a three-phase line having a series impedance of (0.4j2.7) per phase. One of the loads absorbs 560 kVA at 0.707 power factor lagging, and the other 132 kW at unity power factor. The line-to-line voltage at the load end of the line is 2203V. Compute (a) the line-to-line voltage at the source end of the line. (b) the total real and reactive power losses in the three-phase line, and (c) the total three-phase real and reactive power supplied at the sending end of the line. Check that the total three-phase complex power delivered by the source equals the total three-phase comp lex power absorbed by the line and loads.
Two three-phase generators supply a three-phase load through separate three-phase lines. The load absorbs 30 kW at 0.8 power factor lagging. The line impedance is (1.4+j1.6) per phase between generator G1 and the load, and (0.8+j1) per phase between generator G2 and the load. If generator G1 supplies 15 kW at 0.8 poir factor lagging, with a terminal voltage of 460 V line-to-line, determine (a) the voltage at the load terminals. (b) the voltage at the terminals of generator G2, and (c) the real and reactive power supplied by generator G2. Assume balanced operation.