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Question 4 (Homework problem 4.47 in the textbook by Rizzoni) Determine the equivalent impedance seen by the source v, in Figure P4.47 when: vs (t) = 10 cos(4000t + 60°) V, R1 = 8000, R2 = 5000, L= 200mH, C = 70NF 's Figure P4.47 ww

Question 4 (Homework problem 4.47 in the textbook by Rizzoni) Determine the equivalent impedance seen by the source v, in Figure P4.47 when: vs (t) = 10 cos(4000t + 60°) V, R1 = 8000, R2 = 5000, L= 200mH, C = 70NF 's Figure P4.47 ww

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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hello i need to solve thi question, (Homework problem 4.47 in the textbook by Rizzoni) Determine the equivalent impedance seen by the source vs in Figure P4.47 when: vs (t) = 10 cos(4000t + 60°) V, R1 = 800Ω, R2 = 500Ω, L = 200mH, C = 70nF. I have added the given solution, however, I cannot get the last step correct. anny help would be gadly appreciated. 

 

Question 4 (Homework problem 4.47 in the textbook by Rizzoni) Determine the equivalent impedance seen by the source v, in Figure P4.47 when: vs (t) = 10 cos(4000t + 60°) V, R1 = 8000, R2 = 5000, L= 200mH, C = 70nF ER2 's R, Figure P4.47 Solution: Known quantities: R1 = 8000, R2 = 5000, L = 200mH, C = 70NF, vs (t) = 10 cos(4000t + 60°) V %3D Find: The equivalent impedance of the circuit. Analysis: X, = @L=8002 = Z, =+j•X, =+j•80092 1 = 35712= Z =-j.X =-j-35712 Z = Z +Z, = R, + jX, = 500+j-8002 = 943.4/58° 2 %3D Z R, Z. eql 442.9+ j219.7= 494.4226.4° 2 eq2 Z+R, egl 'eq2 494.3+ j168.9 = 490.6Z18.9° Q %3D eq Zw2 + Ze eq2 ww ele ww
Transcribed Image Text:Question 4 (Homework problem 4.47 in the textbook by Rizzoni) Determine the equivalent impedance seen by the source v, in Figure P4.47 when: vs (t) = 10 cos(4000t + 60°) V, R1 = 8000, R2 = 5000, L= 200mH, C = 70nF ER2 's R, Figure P4.47 Solution: Known quantities: R1 = 8000, R2 = 5000, L = 200mH, C = 70NF, vs (t) = 10 cos(4000t + 60°) V %3D Find: The equivalent impedance of the circuit. Analysis: X, = @L=8002 = Z, =+j•X, =+j•80092 1 = 35712= Z =-j.X =-j-35712 Z = Z +Z, = R, + jX, = 500+j-8002 = 943.4/58° 2 %3D Z R, Z. eql 442.9+ j219.7= 494.4226.4° 2 eq2 Z+R, egl 'eq2 494.3+ j168.9 = 490.6Z18.9° Q %3D eq Zw2 + Ze eq2 ww ele ww
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