QUESTION 4 In a Tree structure the first node in the top of the tree called.. O A. Last node O B. Heat node C. Root node D. Head node
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A: Traversal is a common operation performed on data structures.
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A: Required: What is the level of node "K" in the tree below?
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A: Hey, since there are multiple questions posted, we will answer the second question. If you want any…
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A: Lets discuss the soln in the next steps
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Q: c. What is the height of this rooted tree? vo Vz V4 v10, V12 V17 ●V16 V14 V15 V13 « V19 V18
A: Height of rooted tree is maximum length of edge from root to leaf node.
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A: the complete solution is given below:-
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A: the code is in 2nd step:
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Q: ethod for locating the B-tree node wi
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A: The above question is answered in step 2 :-
Q: What Is A Binary Tree
A: In this answer I will be discussing about Binary Tree.
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A: Not a property of a tree
Q: c. What is the height of this rooted tree? vo V5 Vz VA V10 •V12 V17 V16 V14 V15 V13 V19 V18
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- Question 1 class tree: def __init__(self, key): self.key = key self.left = None self.right = None def find_longest_word(self): res = root.data t2 = tree('apple') t2.left = tree('banana') t2.left.right = tree('orange') t2.right = tree('strawberry') t2.right.left = tree('grape') t2.right.left.right = tree('peach') print(find_longest_word) Hello, need help with this python code. Im trying to have a binary tree that can determine which nodes have the longest words. I got stuck on the function part. please help and thank you. It should return strawberry! ......Q2. a. What is a Binary Search Tree? b. Draw the Binary Search Tree that results from the insertion, one at a time, of nodes with Keys 27, 59, 21, 38, 54, 63, 8, 70, 15, 12. (Marking Scheme: Each correct insertion in the tree will give you c. Perform the following operations on the original tree and redraw the tree after each operation ) i.deleting 63 ii.deleting 59 iii.Insert 65 iv.Insert 22 d. Write down the inorder, preorder and postorder traversal on the constructed binary tree.Please answer all the following questions in a Microsoft Word file named: “Name Surname –Assignment 2”. For all the questions, show your calculations and the steps of the searchalgorithm when used. i) Fill in the nodes of the above tree in the order they would be explored in a depth-first search(assume left to right traversal).ii) Compare depth-first searching to breadth-first searching. When are depth-first searches thesuperior choice and why? Give a real-world example.
- Create a Binary Search Tree Class using C++ with the following Operations: Operations: Insert(int n) : Add a node the tree with value n. Its O(lgn) Find(int n) : Find a node the tree with value n. Its O(lgn) Delete (int n) : Delete a node the tree with value n. Its O(lgn) Display(): Prints the entire tree in increasing order. O(n).please, can you help me, I'm working with notebooks python. class Tree: """A rooted binary tree""" def __init__(self): self.root = None self.left = None self.right = None def is_empty(tree: Tree) -> bool: """Return True if and only if tree is empty.""" return tree.root == tree.left == tree.right == None def join(item: object, left: Tree, right: Tree) -> Tree: """Return a tree with the given root and subtrees.""" tree = Tree() tree.root = item tree.left = left tree.right = right return tree The following code builds a binary tree, MORSE, which implements the upper-case Morse code, as per the image below. More information on Morse code can be found on Wikipedia. You will need to run this code block to use in your solutions. EMPTY = Tree()H = join('H',EMPTY,EMPTY)V = join('V',EMPTY,EMPTY)F = join('F',EMPTY,EMPTY)L = join('L',EMPTY,EMPTY)P = join('P',EMPTY,EMPTY)J = join('J',EMPTY,EMPTY)B = join('B',EMPTY,EMPTY)X =…3 // C++ Code. This is all the info that was provided... I don't understand Given the attached Merkle Tree from http://en.wikipedia.org/wiki/Merkle_tree Let L1=Then out spake brave Horatius, The Captain of the Gate: L2="To every man upon this earth Death cometh soon or late. L3=And how can man die better Than facing fearful odds, and L4=For the ashes of his fathers, And the temples of his Gods." Create all hashes 0-0, 0-1, 1-0, 1-1, 0, 1 with top Show all you need to do to confirm L1 is 0-1, 0, top L2 is 0-0, 1, top L3 is 1-1, 0, top and L4 is 1-0, 0, top
- please i need the answer to the whole question. this question has not been asked before so dont use a similar solution. thank you. in c++ create code that does the following(binary search tree) 1 void add(string); // add string in search tree 2 int preorderTrav(node*) // pre order traversing 3 leafcount(node*) //counts number of leaves in search tree 4 void nodeSibling(string) // finds the sibling nodes 5) void searchBT(string) // searches for a node and displays sibling nodes example of run Enter your choice <1-4>: 1 enter number of items to add: 4 enter node: KAM inserted enter node: PAM inserted enter node: DON inserted enter node: TOM inserted enter your choice <1-4> : 2 node info travsersing preorder right child left child info _________ _____________ ___________ KAM DON…C++ Add a new leaf node called nodeM which will possess the data value of M. Make this node the child of nodeB. Perform the findData function you created in #3, what can you observe about the output? /#3 #include<iostream>#include<queue>using namespace std; struct treeNode{ char dataItem; struct treeNode *firstChild; struct treeNode *nextSibling;}; /* Preorder Traversalpreorder (v)visit(v)for each child w of vpreorder(w)*/void preorder(treeNode *currNode, char KEY){ if(currNode != NULL) { if(currNode->dataItem == KEY) { cout<<"KEY: "<<KEY<< " was found!\n"; } preorder(currNode->firstChild, KEY); preorder(currNode->nextSibling, KEY); } return;} /*Inorder Traversalif(v==NULL) returninOrder(v.left)visit(v)inOrder(v.right)*/void inorder(treeNode *currNode, char KEY){ if(currNode != NULL) { if(currNode->dataItem == KEY) { cout<<"KEY:…Question 1111 Computer Science Python. Please write a function to determine if a binary search tree is full. The function receives a reference to the tree "t". def isFull(t):return True
- 1. Construct a binary tree for the numbers 3,4,5,6,7,8,9. Then for each number input taken at runtime, show the number of iterations required to reach that node from root node containing the target number. (10) 2. Construct a binary tree with the following keys as strings a. Desktop, CSU, Spring2022, CIS260, CIS 265, Vacation, Hackathon Your first task is to put this data in an array of string and search for a folder name. Let us say that the folder name is “Hackathon”. Using the array subscript, how many iterations does it take to find the folder? (10) Next, convert this array into a Binary tree and arrange in alphabetical order, and try to find the same folder. List the number of Iterations.(10) Bonus: Now replace the folder names with file contents. So you need a File class where there is a filename variable and file content variable, both should be strings. So the node would have file object instead of just names. So you have an array of File class objects, so the binary tree will…Consider s = (((1) ∗ 2 + 3) ∗ 5 ∗ 6 + 7). 1. Explain how the word s came to be.2. Draw the word s's tree structure.3. Use GetExp to track the execution of your application (s, 1). Draw a tree with a box for each time a routine is called, in other terms. Include only whether it is an expression, word, or factor in each field, as well as the parsed string s[i],..., s[j 1].Help me convert this into java. Thanks a lot! #include<bits/stdc++.h>using namespace std;struct Node{public: int key; struct Node *left,*right;};struct Node *newNode(int data){ Node *temp = (struct Node*)malloc(sizeof(struct Node)); temp->key = data; temp->left = NULL; temp->right = NULL; return temp;}struct Node *insert(Node *node,int key){ if(node == NULL) return newNode(key); if(key<node->key) node->left = insert(node->left,key); else if(key>node->key) node->right = insert(node->right,key); return node;} int maxDepth(Node* node) { if (node == NULL) return 0; else { int lDepth = maxDepth(node->left); int rDepth = maxDepth(node->right); if (lDepth > rDepth) return(lDepth + 1); else return(rDepth + 1); } } int main(){ int t; cin>>t; while(t--) { int n; cin>>n; int…