Question 6To begin evaluating sin*xcos°xdx conveniently, express:A sin'x as (sin²x)²and use the identity sin²x =1- cos?x® sin'x as (sin'x)?and use the Half – Angle Formula sin?x = - (1– sin²21)© cos'x as (cos?x)?cosr and use the identity cos?x =1= sin?xcos x as (cos²x)?cosx and use the Half – Angle Formula cos²x=-(1+ cos2r)(E) None

Here we put cos^5x as (cos^2x)^2 cos x and then Use the identity cos^2x=1-sin^2x.

Question 6 To begin evaluating J sintrecor^rdx comvenienty, express: sin'x as (sin²x) ²and use the identity sin²x = 1 – cos?x B sin'x as (sin²x)²and use the Half – Angle Formula sin?x = - (1– sin°2x) cos'x as (cos²x)²cosx and use the identity cos?x = 1– sin²x D cos'x as (cos?x)²cosx and use the Half - Angle Formula cos²x=-(1+cos2x) (E) None

Question 6 To begin evaluating J sintrecor^rdx comvenienty, express: sin'x as (sin²x) ²and use the identity sin²x = 1 – cos?x B sin'x as (sin²x)²and use the Half – Angle Formula sin?x = - (1– sin°2x) cos'x as (cos²x)²cosx and use the identity cos?x = 1– sin²x D cos'x as (cos?x)²cosx and use the Half - Angle Formula cos²x=-(1+cos2x) (E) None

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter6: The Trigonometric Functions

Section6.3: Trigonometric Functions Of Real Numbers

Problem 21E

See similar textbooks