Question 7 3. Solve: 4 = ( dy 2y+3 4x+5 dr +C (4z+5)² - (2y+3)² 1 +C (4z+5)² %3D (2y+3)? 1 (2y+3)? +C (4z+5)? 1 +C (4z+5)² (2y+3)² (2y+3)² 1 +C (4z+5)? (2y+3)² 1 +C (4z+5)² II 2.

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