Question 7. Suppose F is a vector field defined on {(x, y, z) # (0,0,0)} such that on the (r, y)-plane (i.e. when z = 0), F(7,y,0) = (- 22 + 4y2' g2 + 4ya0), (2, y) # (0,0). (a) Let C be the closed curve defined by {(r, y,0) : z² + 4y2 4}, oriented counterclockwise %3D when viewed from above. Directly compute (by parametrizing the curve) the circulation F.Tds = F. dr.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.6: Additional Trigonometric Graphs
Problem 78E
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Question 7, Suppose F is a vector field defined on {(x, y, z) # (0,0,0)} such that on the (r, y)-plane (i.e.
when z = 0),
F(z, y,0) = (-
,0), (z,y) # (0,0).
22 + 4y²' x² + 4y² '
Let C be the closed curve defined by {(x, y, 0) : 2 + 4y²
(a)
when viewed from above. Directly compute (by parametrizing the curve) the circulation
= 4}, oriented counterclockwise
F. Tds =
F. dr.
(b)
Note that we only know the exact expression of F on the (x, y)-plane. Explain why F cannot
satisfy curlF = (0,0,0) in {(x,y,z) # (0,0, 0)}, no matter how it is defined outside the (x, y)-plane.
Transcribed Image Text:Question 7, Suppose F is a vector field defined on {(x, y, z) # (0,0,0)} such that on the (r, y)-plane (i.e. when z = 0), F(z, y,0) = (- ,0), (z,y) # (0,0). 22 + 4y²' x² + 4y² ' Let C be the closed curve defined by {(x, y, 0) : 2 + 4y² (a) when viewed from above. Directly compute (by parametrizing the curve) the circulation = 4}, oriented counterclockwise F. Tds = F. dr. (b) Note that we only know the exact expression of F on the (x, y)-plane. Explain why F cannot satisfy curlF = (0,0,0) in {(x,y,z) # (0,0, 0)}, no matter how it is defined outside the (x, y)-plane.
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