Question: A lumber company needs to compute the values of certain engineering properties of its rectangular cross section lumber. The dimensions of the wood are given as base and height in inches as integers. The required engineering properties are: cross sectional area = base x height base x height moment of inertia = 12.0 base x height? section modulus = 6.0 Write a program which reads the base and height from the user then calls three functions area(), inertia(), and modulus() to compute the values of the required engineering properties. The program then prints the three values to the screen. Note that you must write your functions so that modulus() calls area() and inertia() calls modulus(). Your program output must look like: Enter the base and height: 2 8 = 16.00 = 85.33 = 21.33 The cross sectional area The moment of inertia The section modulus
Question: A lumber company needs to compute the values of certain engineering properties of its rectangular cross section lumber. The dimensions of the wood are given as base and height in inches as integers. The required engineering properties are: cross sectional area = base x height base x height moment of inertia = 12.0 base x height? section modulus = 6.0 Write a program which reads the base and height from the user then calls three functions area(), inertia(), and modulus() to compute the values of the required engineering properties. The program then prints the three values to the screen. Note that you must write your functions so that modulus() calls area() and inertia() calls modulus(). Your program output must look like: Enter the base and height: 2 8 = 16.00 = 85.33 = 21.33 The cross sectional area The moment of inertia The section modulus
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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