QUESTION B11 A vase with a circular cross-section is shown in Figure 1. Water is flowing into the vase. When the depth of the water is h cm, the volume of the water V cm³ is given by: V = 4th² + 16th, 0shs 25 h cm Water flows into the vase at a constant rate of 80n cm³s-1. Find the rate of change of the depth of the water, in cms-1, when h = 6 Figure 1 А. 1.5 ст/s В. О.8 ст/s С. 1.2 ст/s D. 2.2сm/s
QUESTION B11 A vase with a circular cross-section is shown in Figure 1. Water is flowing into the vase. When the depth of the water is h cm, the volume of the water V cm³ is given by: V = 4th² + 16th, 0shs 25 h cm Water flows into the vase at a constant rate of 80n cm³s-1. Find the rate of change of the depth of the water, in cms-1, when h = 6 Figure 1 А. 1.5 ст/s В. О.8 ст/s С. 1.2 ст/s D. 2.2сm/s
Chapter6: Exponential And Logarithmic Functions
Section: Chapter Questions
Problem 51RE: The population of a city is modeled by the equation P(t)=256,114e0.25t where t is measured in years....
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Transcribed Image Text:QUESTION B11
A vase with a circular cross-section is shown in Figure 1. Water
is flowing into the vase. When the depth of the water is h cm, the
volume of the water V cm³ is given by:
V = 4th? + 16xth,
h cm
0shs 25
Water flows into the vase at a constant rate of 80n cm's-1. Find
Figure 1
the rate of change of the depth of the water, in cms-1, when h = 6
%3D
А. 1.5 ст/s
В. О.8 ст/s
С. 1.2 ст/s
D. 2.2cm/s
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