Question Consider Kepler's equation regarding planetary orbits, given as M = E – e sin(E), where M is the mean anomaly, E is the eccentric anomaly, and e measures eccentricity. Find the eccentric anomaly E when the mean anomaly M = and the eccentricity of the orbit e = 0.91. Use Newton's method with initial approximation 7. Xo = 3 to find x2, rounded to the nearest thousandth. Provide your answer below:

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