Question no.1 The vessel in Example 1.7.2 is going to discharge (- minus) two parts of the cargo: Cargo no.5 = 300 tons distance from App ( pt.A) 84.3 meters %3D And Cargo no.6 = 500 tons distance from App ( pt. A) Find the new Longitudinal Center of Gravity (Vertical Center of Gravity problem) Question no. 2 Ship MS Linda is to load for her next port as in example in 1.7.4. The Vertical Center of Gravity ( VCG) is as VCG cargo hold on below as follows. Displacement before loading is 11, 495 tons with VCG of 7.74 meters from Keel. To load ( plus + the weights and moments) Hold no. 2 = 2,000 tons distance from keel7.14 mtrs Hold no. 4 = 2,500 tons distance from keel 7.13 mtrs Hold no.6 = 3,000 tons distance from keel 7.74 mtrs Find the new Vertical Center of Gravity( VCG) after
Question no.1 The vessel in Example 1.7.2 is going to discharge (- minus) two parts of the cargo: Cargo no.5 = 300 tons distance from App ( pt.A) 84.3 meters %3D And Cargo no.6 = 500 tons distance from App ( pt. A) Find the new Longitudinal Center of Gravity (Vertical Center of Gravity problem) Question no. 2 Ship MS Linda is to load for her next port as in example in 1.7.4. The Vertical Center of Gravity ( VCG) is as VCG cargo hold on below as follows. Displacement before loading is 11, 495 tons with VCG of 7.74 meters from Keel. To load ( plus + the weights and moments) Hold no. 2 = 2,000 tons distance from keel7.14 mtrs Hold no. 4 = 2,500 tons distance from keel 7.13 mtrs Hold no.6 = 3,000 tons distance from keel 7.74 mtrs Find the new Vertical Center of Gravity( VCG) after
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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