Question no.1 The vessel in Example 1.7.2 is going to discharge (- minus) two parts of the cargo: Cargo no.5 = 300 tons distance from App ( pt.A) 84.3 meters %3D And Cargo no.6 = 500 tons distance from App ( pt. A) Find the new Longitudinal Center of Gravity (Vertical Center of Gravity problem) Question no. 2 Ship MS Linda is to load for her next port as in example in 1.7.4. The Vertical Center of Gravity ( VCG) is as VCG cargo hold on below as follows. Displacement before loading is 11, 495 tons with VCG of 7.74 meters from Keel. To load ( plus + the weights and moments) Hold no. 2 = 2,000 tons distance from keel7.14 mtrs Hold no. 4 = 2,500 tons distance from keel 7.13 mtrs Hold no.6 = 3,000 tons distance from keel 7.74 mtrs Find the new Vertical Center of Gravity( VCG) after

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
icon
Related questions
Question

Please answer both questions

Question no.1
The vessel in Example 1.7.2 is going to discharge
(- minus) two parts of the cargo:
Cargo no.5 = 300 tons distance from App ( pt.A)
84.3 meters
And
Cargo no.6 = 500 tons distance from App ( pt. A)
%3D
Find the new Longitudinal Center of Gravity
(Vertical Center of Gravity problem)
Question no. 2
Ship MS Linda is to load for her next port as in
example in 1.7.4. The Vertical Center of Gravity
( VCG) is as VCG cargo hold on below as follows.
Displacement before loading is 11, 495 tons with
VCG of 7.74 meters from Keel.
To load ( plus + the weights and moments)
Hold no. 2 = 2,000 tons distance from keel 7.14
%3D
mtrs
Hold no. 4 = 2,500 tons distance from keel 7.13
mtrs
Hold no.6 = 3,000 tons distance from keel 7.74
mtrs
Find the new Vertical Center of Gravity( VCG) after
Transcribed Image Text:Question no.1 The vessel in Example 1.7.2 is going to discharge (- minus) two parts of the cargo: Cargo no.5 = 300 tons distance from App ( pt.A) 84.3 meters And Cargo no.6 = 500 tons distance from App ( pt. A) %3D Find the new Longitudinal Center of Gravity (Vertical Center of Gravity problem) Question no. 2 Ship MS Linda is to load for her next port as in example in 1.7.4. The Vertical Center of Gravity ( VCG) is as VCG cargo hold on below as follows. Displacement before loading is 11, 495 tons with VCG of 7.74 meters from Keel. To load ( plus + the weights and moments) Hold no. 2 = 2,000 tons distance from keel 7.14 %3D mtrs Hold no. 4 = 2,500 tons distance from keel 7.13 mtrs Hold no.6 = 3,000 tons distance from keel 7.74 mtrs Find the new Vertical Center of Gravity( VCG) after
Expert Solution
steps

Step by step

Solved in 3 steps

Blurred answer
Knowledge Booster
Stresses in saturated soil without seepage
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Structural Analysis
Structural Analysis
Civil Engineering
ISBN:
9781337630931
Author:
KASSIMALI, Aslam.
Publisher:
Cengage,
Structural Analysis (10th Edition)
Structural Analysis (10th Edition)
Civil Engineering
ISBN:
9780134610672
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Principles of Foundation Engineering (MindTap Cou…
Principles of Foundation Engineering (MindTap Cou…
Civil Engineering
ISBN:
9781337705028
Author:
Braja M. Das, Nagaratnam Sivakugan
Publisher:
Cengage Learning
Fundamentals of Structural Analysis
Fundamentals of Structural Analysis
Civil Engineering
ISBN:
9780073398006
Author:
Kenneth M. Leet Emeritus, Chia-Ming Uang, Joel Lanning
Publisher:
McGraw-Hill Education
Sustainable Energy
Sustainable Energy
Civil Engineering
ISBN:
9781337551663
Author:
DUNLAP, Richard A.
Publisher:
Cengage,
Traffic and Highway Engineering
Traffic and Highway Engineering
Civil Engineering
ISBN:
9781305156241
Author:
Garber, Nicholas J.
Publisher:
Cengage Learning