Question public class MyProgram ( if (h <18) { public static void main(String[] args) { int h=10, t-22; System.out.print ("Good "); } What is the output displayed by the following lines of code?" } else } System.out.print ("Morning"); t = t + 2; if (t > 30) system.out.print("Evening"); t = t + 5; System.out.println(" Every One!"); System.out.println("The temperature is " + System.out.println(" Brink water?"); Degree.");
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- public class LabProgram { public static void main(String args[]) { Course cis162 = new Course(); int beforeCount; String toDrop; // Example students for testing cis162.addStudent(new Student("Henry", "Nguyen", 3.5)); cis162.addStudent(new Student("Brenda", "Stern", 2.0)); cis162.addStudent(new Student("Lynda", "Robison", 3.2)); cis162.addStudent(new Student("Sonya", "King", 3.9)); toDrop = "Stern"; beforeCount = cis162.countStudents(); cis162.dropStudent(toDrop); System.out.println("Course size: " + beforeCount + " students"); System.out.println("Course size after drop: " + cis162.countStudents() + " students"); } } import java.text.DecimalFormat; // Class representing a student public class Student { private String first; // first name private String last; // last name private double gpa; // grade point average // Student class constructor public Student(String f, String l, double g) {…T/F Java methods can return more than one item if they are modified with the reserved word continue, as in public continue int foo() {...}Subject - Data Structure Please help me to debug my error. Thank you in advance! import java.util.Scanner;public class LinearSearchDemo { private static int linearSearch(int[] numbers, int key) { for (int i = 0; i < numbers.length; i++) { if (numbers[i] == key) { return i; } } return -1; // not found } // Main program to test the linearSearch() method public static void main(String[] args) { int[] numbers = { 2, 4, 7, 10, 11, 32, 45, 87 }; System.out.print("NUMBERS: "); for (int i = 0; i < numbers.length; i++) { System.out.print(numbers[i] + " "); } System.out.println(); Scanner scnr = new Scanner(System.in); System.out.print("Enter an integer value: "); int key = scnr.nextInt(); int keyIndex = linearSearch(numbers, key); if (keyIndex == -1) { System.out.println(key + " was not found."); } else { System.out.printf("Found %d at index…
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- 1. Find the statement that causes the compilation error. 2. Determine the output if that statement is removed. class A { public void test() { System.out.print("A"); } } class B extends A { public void test() { System.out.print("B"); } } public class C extends A { public void test() { System.out.print("C"); } public static void main(String[ ] args) { A b1 = new A( ); A b2 = new C( ); b1 = (A)b2; A b3 = (B)b2; b1.test( ); b2.test( ); } }Java Questions - (Has 2 Parts). Based on each code, which answer out of the choices "A, B, C, D, E" is correct. Each question has one correct answer. Thank you. Part 1 - Given the following code, the output is __. class Sample{ public static void main (String[] args){ try{ System.out.println(5/0);}catch(ArithmeticException e){ System.out.print("Divide by zero????");}finally{ System.out.println("5/0"); } }} A. Divide by zero????B. 5/0C. Divide by zero????5/0D. 5/0Divide by zero????E. "5/0" Part 2 - Given the following code, the output is __. try{ Integer number = new Integer("1"); System.out.println("An Integer instance.");}catch (Exception e){ System.out.println("An Exception.");} A. An Integer instance.B. An Exception.C. 1D. Error: ExceptionE. None of the optionsPROBLEM STATEMENT: Use string concatenation to append the "dogs" string to the parameter str. public class StringConcatAppend{public static String solution(String str){// ↓↓↓↓ your code goes here ↓↓↓↓return null;}} Can you help me with this question the lannguage is Java
- Order check Write a program OrderCheck.java that takes four int command-line arguments w, x, y, and z. Define a boolean variable whose value is true if the four values are either in strictly ascending order (w < x < y < z) or strictly descending order (w > x > y > z), and false otherwise. Then, display the boolean variable value.WeShipIt.java:39: error: illegal start of expression public static String getItemDescription(Scanner console) ^ still shoewing thisProblem Description. Arguments for the main method are passed as strings. Strings enclosed in quotation marks are considered as one argument. Write a program to parse arguments from a string. Arguments are separated by spaces. Enclosed strings are considered as one argument. Your program should prompt the user to enter a string and display the arguments, each per line, as shown in the following sample run. <input> Enter the arguments: a friend "good morning" "good afternoon" b <output> a friend good morning good afternoon b please provide the answer in JAVA