Question Suppose that the piecewise function f is defined by v2 +4, -6z+v6+5, z>1 -2

College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter3: Functions
Section3.1: Functions And Function Notation
Problem 92SE: Show that the function f(x)=3(x5)2+7 is not one-to-one.
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Suppose that the piecewise function f is defined by
SV2 +4,
-6z + v6+5, z>1
f(x) =
-2<z<1
Determine which of the following statements are true.
Select the correct answer below:
O f(z) is not continuous at r = 1 because it is not defined atz 1.
O f(1) exists, but f(r) is not continuous at z 1 because lim f(x) does not exist.
O () and lim f(r) both exist, but f(z) isnot continuous at z 1 because lim f(z) f(1).
O f(2) is continuous at r = 1.
Transcribed Image Text:Question Suppose that the piecewise function f is defined by SV2 +4, -6z + v6+5, z>1 f(x) = -2<z<1 Determine which of the following statements are true. Select the correct answer below: O f(z) is not continuous at r = 1 because it is not defined atz 1. O f(1) exists, but f(r) is not continuous at z 1 because lim f(x) does not exist. O () and lim f(r) both exist, but f(z) isnot continuous at z 1 because lim f(z) f(1). O f(2) is continuous at r = 1.
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