Question Which of the following is the solution of the DE (a? + 4) y' = y (2y² + 1) tan - A 2y2 + C y 2 e +2 = 0 B None of the above tan 2y2 + C y 2 e +1 = 0 -tan -1 D 2y²+Cy²e +1=0 -tan - E 2y2+ Cy?e +2=0

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
Which of the following is the solution of the DE (x? + 4) y' = y (2y? + 1)
tan
(A) 2y² + C y 2 e
+2 = 0
B None of the above
(9),
tan -I
2y2 + C y 2e
+1 = 0
-tan -1
D 2y2+ Cy?e
+1=0
-tan -1
E 2y2+ Cy?e
+2=0
Transcribed Image Text:Question Which of the following is the solution of the DE (x? + 4) y' = y (2y? + 1) tan (A) 2y² + C y 2 e +2 = 0 B None of the above (9), tan -I 2y2 + C y 2e +1 = 0 -tan -1 D 2y2+ Cy?e +1=0 -tan -1 E 2y2+ Cy?e +2=0
Question
The differential equation (3x + 2y + 1) dx + ( x –3y - 7) dy = 0 can be transformed into
homogeneous DE by substituting x = u +h and y = v + k where
(A) h = 1 and k = - 2
B)
h = 1 and k =
2
None of the above
(D) h = - 1 and k =
- 2
E)
h = -1 and k
= 2
Transcribed Image Text:Question The differential equation (3x + 2y + 1) dx + ( x –3y - 7) dy = 0 can be transformed into homogeneous DE by substituting x = u +h and y = v + k where (A) h = 1 and k = - 2 B) h = 1 and k = 2 None of the above (D) h = - 1 and k = - 2 E) h = -1 and k = 2
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