Answered: R5 R4 220V R3 R2 R6

Engineering

Electrical Engineering

R5 R4 220V R3 R2 R6

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter7: Parallel Circuits

Section: Chapter Questions

Problem 3PP: Using the rules for parallel circuits and Ohmslaw, solve for the missing values....

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Concept explainers

Electrical Heating Unit

The conversion of electrical energy to heat energy is known as electric heating. The heating system that converts the electrical energy to heat energy for various application is called electrical heating unit. Electricity is employed as the firing mechanism in electric heating systems, which transforms electric current to heat. Electric heaters have heating elements in the form of electric resistors.

Question

To determine the value of the resistances of the lightbulbs, look for the POWER (watt) and VOLTAGE DROP (V=220V) on the label of your lightbulbs. Then, use the derived formula of power (R = V2 / P) to get the resistance of each lightbulb.

After getting the resistance of each lightbulb, compute the total and individual values of the resistance, current, and voltage using the process of solving resistors in circuit following the GAFSA (Given, Asked, Formula, Solution, and Answer) format.

Given:

V_T= 220V
P₁ = 2.5w
P₂ = 2.5w
P₃ = 2.5w
P₄ = 10w
P₅ = 5w
P₆ = 5w
P₇ = 5w
P₈ = 10w
P₉ = 6w
P₁₀ = 6w

FORMULA:
V
R =
V = RI
For resistors in series:
For resistors in parallel:
Rtotal = Ri+R2+...
R2
R1
Itotal = 1+l2+...
Vtotal = V1 = V2 = ...
Rrotal
Viotal = Vi+V2+...
Itotal = l1 = l2 = ..

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