Reading Section 1.6-1.8 Problem Prove the following theorem: Theorem Vn E Z, n is either even or odd (but not both). Your proof must address the following points: 1. n is even or odd (and nothing else). 2. n is odd = n is not even (hint: contradiction). 3. n is even → n is not odd (hint: contrapositive). The first point is a bit more difficult. Start by making a statement about 0. Then assuming that n is even, what can you say about n – 1 and n + 1? Likewise, assuming that n is odd, what can - 1 and n + 1. Can you organize these facts into an argument that shows that you say about n you have accounted for all possible n E Z?

Linear Algebra: A Modern Introduction
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ISBN:9781285463247
Author:David Poole
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Chapter2: Systems Of Linear Equations
Section2.4: Applications
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Reading
Section 1.6-1.8
Problem
Prove the following theorem:
Theorem
Vn E Z, n is either even or odd (but not both).
Your proof must address the following points:
1. n is even or odd (and nothing else).
2. n is odd =
n is not even (hint: contradiction).
3. n is even
→ n is not odd (hint: contrapositive).
The first point is a bit more difficult. Start by making a statement about 0. Then assuming that
n is even, what can you say about n – 1 and n + 1? Likewise, assuming that n is odd, what can
- 1 and n + 1. Can you organize these facts into an argument that shows that
you say about n
you have accounted for all possible n E Z?
Transcribed Image Text:Reading Section 1.6-1.8 Problem Prove the following theorem: Theorem Vn E Z, n is either even or odd (but not both). Your proof must address the following points: 1. n is even or odd (and nothing else). 2. n is odd = n is not even (hint: contradiction). 3. n is even → n is not odd (hint: contrapositive). The first point is a bit more difficult. Start by making a statement about 0. Then assuming that n is even, what can you say about n – 1 and n + 1? Likewise, assuming that n is odd, what can - 1 and n + 1. Can you organize these facts into an argument that shows that you say about n you have accounted for all possible n E Z?
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