Rearrange the following lines of code to produce a program that finds the second uppercase letter in a string. Not all lines are useful.
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- public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string.This problem is an exercise in Java string manipulation. For some mysterious reason, the Java String type does not come with a reverse method. The canonical way to reverse a Java string str is to first convert it to mutable StringBuilder, reverse its contents, and convert the result back to an immutable string, that is,str = new StringBuilder(str).reverse().toString(); Here's the tester it must pass: @Test public void testPancakeScramble() throws IOException {// Explicit test casesassertEquals("", P2J3.pancakeScramble(""));assertEquals("alu",…public static String[] getTokens(String raw, String delimiter){ // Line #1 goes here... int numTokens = st.countTokens(); // Line #3 goes here... for(int i = 0; i < numTokens; i++){ // Line #5 goes here } // Line #7 goes here } Using the code above, which one of these should be the code for "Line #7": ret[i] = st.nextToken(); return ret; String[] ret = new String[numTokens]; StringTokenizer st = new StringTokenizer(raw, delimiter);Question 10 Create a class that implements a compressed trie for a set of strings. The class should have a constructor that takes a list of strings as an argument, and the class should have a method that tests whether a given string is stored in the trie. JAVA PLZ! . . .
- DescriptionA researcher is analyzing DNA. A DNA can be represented as a string composed of the characters A, G, C, or T.One day, researchers found a strange DNA, which is Smooth Repeated DNA. The DNA is represented by a string that has infinite length. The string has a repeating pattern, i.e. the DNA string 0 is repeated an infinite number of times. For example, if0 = "????", then = "???????????? . . . ".According to researchers, a DNA is said to be special if it contains substrings . Determine whetheris a substring of . Squad FormatA line containing the two strings 0 and . Output FormatA line that determines whether it is a substring of . Issue “YES” ifis a substring of . Output “NO” otherwise. Example Input and Output Input Example Example Output AGCT GC YES AGCT TA YES AGCT GT No AGCT TAGCTAGCT YES AGGACCTA CTAA YES Explanation ExampleIn the first to fourth test case examples, is worth "???????????? . . . ". The part in bold is one of the…/* This is the code for the Word Jumble game from Chapter 3. Improve the Word Jumble game by adding a scoring system. Make the point valuefor a word based on its length. Deduct points if the player asks for a hint. */ // Word Jumble// The classic word jumble game where the player can ask for a hint #include <iostream>#include <string>#include <cstdlib>#include <ctime> using namespace std; int main(){ enum fields {WORD, HINT, NUM_FIELDS}; const int NUM_WORDS = 5; const string WORDS[NUM_WORDS][NUM_FIELDS] = { {"wall", "Do you feel you're banging your head against something?"}, {"glasses", "These might help you see the answer."}, {"labored", "Going slowly, is it?"}, {"persistent", "Keep at it."}, {"jumble", "It's what the game is all about."} }; srand(static_cast<unsigned int>(time(0))); int choice = (rand() % NUM_WORDS); string theWord = WORDS[choice][WORD]; //word to guess string theHint =…Kindly fix the error in the code... It's just a error. So kindly try to fix it & don't change the things. We are waiting for ur response. Thanks. #include<iostream>#include<stdlib.h>#include<string>using namespace std; class universityPersonnel{public:string name; virtual void getData() = 0; virtual void isoutstanding() = 0; void input(){cout << "Enter name : ";getline(cin, name);} void display(){cout << "Personnel Information : \n";cout << "Name : " << name << endl;}}; class student : public universityPersonnel{public:double gpa; student(){gpa = 0;}void getData(){input();cout << "Enter GPA : ";cin >> gpa;}void isoutstanding(){if (gpa > 3){cout << "GPA is greater than 3. Outstanding! \n";}else{cout << "GPA is less than 3 which is not outstanding \n";}}}; class instructor : public universityPersonnel{public:int publications; instructor(){publications = 0;}void getData(){input();cout << "Enter…
- IN JAVA Create a function that takes a string and returns the number of alphanumeric characters that occur more than once. Examples duplicateCount ("abcde") → 0 duplicateCount ("aabbcde") → 2 duplicateCount ("Indivisibilities") → 2 duplicateCount ("Aa") → 0 // Case sensitivepublic void OnSend(View v){ String phoneNumber = number.getText().toString(); String smsmessage = message.getText().toString(); if(phoneNumber == null || phoneNumber.length() == 0 || smsmessage == null || smsmessage.length() == 0){ return; } if(checkPermission(Manifest.permission.SEND_SMS)){ SmsManager smsManager = SmsManager.getDefault(); smsManager.sendTextMessage(phoneNumber, null, smsmessage, null, null); Toast.makeText(this, "Message sent", Toast.LENGTH_SHORT).show(); } Question 2: Explain the following code: button.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { FragmentManager fm = getSupportFragmentManager(); FragmentTransaction ft = fm.beginTransaction(); XFragment xfragment = new XFragment(); ft.add(R.id.Main_fragment, xfragment);…Please help me with this task. Thank you! public class CustomString { String myString; boolean isSet; public CustomString() { this.myString = null; this.isSet = false; } /** * Returns a new string version of the current string where the alphabetical characters specified in the given arg, are removed. * * The alphabetical characters to be removed are case insensitive. * All non-alphabetical characters are unaffected. * If the current string is null, empty, or has not been set to a value, this method should return an empty string. * * Example(s): * - For a current string "my lucky numbers are 6, 8, and 19.", calling remove("ra6") would return "my lucky numbes e 6, 8, nd 19." * - For a current string "my lucky numbers are 6, 8, and 19.", calling remove("6,.") would return "my lucky numbers are 6, 8, and 19." * - For a current string "my lucky numbers are 6, 8, and 19.", calling remove("") would return "my…
- A premutation of three objects a, b, and cm is any arrangement of these objects in a row. For example, some of the premutations of thee objects are abc, bca, and cab. The number of premutations of three objects is 6. Suppose thst these three objects are strings. Write a program that prompts the user to enter three Stings. The program then outputs the six premutations of those strings. This program must be in Java. Thank youEx: Use getline() to get a line of user input into a string. Output the line. Enter text: IDK if I'll go. It's my BFF's birthday. You entered: IDK if I'll go. It's my BFF's birthday. Search the string (using find()) for common abbreviations and print a list of each found abbreviation along with its decoded meaning. Ex: Enter text: IDK if I'll go. It's my BFF's birthday. You entered: IDK if I'll go. It's my BFF's birthday. BFF: best friend forever IDK: I don't know Support these abbreviations: BFF -- best friend forever IDK -- I don't know . JK -- just kidding TMI -- too much information TTYL-talk to you later 1 #include 2 // FIXME include the string Library 3 using namespace std; 4 5 int main() { 6 7 8 9 10 } /* Type your code here. */ return 0; main.cpp// Converts a string to lowercase, and // displays the string's length// as well as a count of letterspublic class DebugSeven4{public static void main(String[] args){String aString = "HELP!! I need to get 37 things DONE today!!";int numLetters = 0.int stringLength = aString.Length();System.out.println("In all lowercase, the sentence is: ");for(int i = 0; i < stringLength; i++){char ch = Character.toTheLowerCase(aString.charAt(i));System.out.print(ch);if(Character.isLetter(ch))numLetters--;}System.out.println();System.out.println("The number of CHARACTERS in the string is " + stringLength);System.out.println(The number of LETTERS is " + numLetters);}}