Recall that at time t the Poisson process N(t) is a Poisson random variable with parameter Xt. We can think of N(t) as counting the number of points in an interval (0, t] if we start at 0 as the origin (the meaning of these points depends on the application). Now define a new random process as X(t) = 1 if N(t) is even and X(t) = − 1 if N(t) is odd. Note that N(0) = 0 so X(0) = 1. i. Compute E[X(t)]. Simplify your result as much as possible. ii. As noted above X(0) = 1 (since N(0) = 0) and is not random. To remove this certainty we form a new random process Y(t) = A · X(t) where A is a random variable taking values +1 and −1 with equal probability. One can show that Y(t) is WSS with covariance function Ky(7) = e−²\|7|. Determine (mathematically) whether or not Y(t) is ergodic in mean.

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Chapter1: Combinatorial Analysis
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b. Recall that at time t the Poisson process N(t) is a Poisson random
variable with parameter At. We can think of N(t) as counting the
number of points in an interval (0, t] if we start at 0 as the origin (the
meaning of these points depends on the application). Now define a new
random process as X(t) = 1 if N(t) is even and X(t) = -1 if N(t) is
odd. Note that N(0) = 0 so X (0) = 1.
www.
i. Compute E[X(t)]. Simplify your result as much as possible.
ii. As noted above X(0) = 1 (since N(0) = 0) and is not random.
To remove this certainty we form a new random process Y(t) =
A. X(t) where A is a random variable taking values +1 and -1
with equal probability. One can show that Y(t) is WSS with
covariance function Ky(T) = e-27. Determine (mathematically)
whether or not Y(t) is ergodic in mean.
Transcribed Image Text:b. Recall that at time t the Poisson process N(t) is a Poisson random variable with parameter At. We can think of N(t) as counting the number of points in an interval (0, t] if we start at 0 as the origin (the meaning of these points depends on the application). Now define a new random process as X(t) = 1 if N(t) is even and X(t) = -1 if N(t) is odd. Note that N(0) = 0 so X (0) = 1. www. i. Compute E[X(t)]. Simplify your result as much as possible. ii. As noted above X(0) = 1 (since N(0) = 0) and is not random. To remove this certainty we form a new random process Y(t) = A. X(t) where A is a random variable taking values +1 and -1 with equal probability. One can show that Y(t) is WSS with covariance function Ky(T) = e-27. Determine (mathematically) whether or not Y(t) is ergodic in mean.
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