Recall that I(n) = (1 - x²)"dr. == 2.1 Substitute x = sin(t) in I(n) and show that I(n) can be written as I(n) = √12 π/2 (cos(t))2n+1dt -π/2 2.2 Now that we have I(n) = f(cos(t))2n+1dt. What is I(n - 1)? Leave your answer in integral form.

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