Recall the integration by parts formuala: Complete the following computation g(x) = = 1. Find f'(x) and g(x) where g(x) has no constant term: f'(x) = 3e³ 3x cos (5x) 5 [ f(x)g'(x)dx = f(x)g(x) — [ f'(x)g(x)dx = 2. Using the integration by parts formula, 3x [e³² sin(5x)da 3x [e³² e³* sin(5x) dx via integration by parts. Set 3x f(x) = = e³_ and _g'(x) = sin(5x) = F(x) - [G(x)dx F(x) = G(x) = 3. Using integration by parts to compute 3x [e³* sin(5x)da [G(x)dr, F(x) – (H(x) − c f e³² sin(5x)da) - H(x) = = C= 4. Use (1), (2), (3) to compute 3x 1e³2 e³* sin(5x) dx = = find H(x) and a constant c such tha

Calculus: Early Transcendentals
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Chapter1: Functions And Models
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Recall the integration by parts formuala:
Complete the following computation
g(x)
=
1. Find f'(x) and g(x) where g(x) has no constant term:
f'(x) = 3eº 3x
cos (5x)
5
[ f(x)g'(x)dx = f(x)9(x) — [ f'(x)g(x) dx
3x
[e³= sin(5x)dr
=
2. Using the integration by parts formula,
3x
1 e³* sin(5x) dx via integration by parts. Set
=
3x
ƒ(x) = e³ and g'(x) = sin(5x)
F(x) - | G(x)da
-
F(x) =
G(x) =
3. Using integration by parts to compute
[e³* sin(5x)da
C =
4. Use (1), (2), (3) to compute
F(@) - (H(a) - c / e*sin(5a)da
с e³
dx
H(x)
[G(a)da, find H(a) and a constant c such that
=
| e³ª sin(5x)dx =
Transcribed Image Text:Recall the integration by parts formuala: Complete the following computation g(x) = 1. Find f'(x) and g(x) where g(x) has no constant term: f'(x) = 3eº 3x cos (5x) 5 [ f(x)g'(x)dx = f(x)9(x) — [ f'(x)g(x) dx 3x [e³= sin(5x)dr = 2. Using the integration by parts formula, 3x 1 e³* sin(5x) dx via integration by parts. Set = 3x ƒ(x) = e³ and g'(x) = sin(5x) F(x) - | G(x)da - F(x) = G(x) = 3. Using integration by parts to compute [e³* sin(5x)da C = 4. Use (1), (2), (3) to compute F(@) - (H(a) - c / e*sin(5a)da с e³ dx H(x) [G(a)da, find H(a) and a constant c such that = | e³ª sin(5x)dx =
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