7.1Refer to the constant-head arrangement shown in Figure 7.5.For a test, the following are given:L = 450 mmA = area of the specimen = 23 cm²Constant-head difference = h = 700 mm%3DWater collected in 3 min =350 cm3Calculate the hydraulic conductivity (cm/s). hGraduated flaskPorous stoneSoil specimenFIGURE 7.5 Constant-head permeability test

WE KNOW RELATIONk=QLAhtQ=total volume of waterL=lengthA=Area of cross-sectionh=headt=time

Answered: Refer to the constant-head arrangement…

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter7: Seepage

Section: Chapter Questions

Problem 7.1P

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Solve for the ratio of equivalent hydraulic conductivity with the following given: h1 = 2 m h2 = 2.5 m h3 = 1.8 m h4 = 0.9 m k1 = 1.5E-3 cm/sec k2 = 2.2E-4 cm/sec k3 = 1.6E-4 cm/sec k4 = 4.0E-4 cm/sec What is the equivalent coefficient of permeability if the water flows perpendicular to the layer of soil (KeqV) in cm/sec?
Solve for the ratio of equivalent hydraulic conductivity with the following given: h1 = 2 m h2 = 2.5 m h3 = 1.8 m h4 = 0.9 m k1 = 1.5E-3 cm/sec k2 = 2.2E-4 cm/sec k3 = 1.6E-4 cm/sec k4 = 4.0E-4 cm/sec What is the equivalent coefficient of permeability if the water flows parallel to the layer of soil (KeqH) in cm/sec?
A constant-head test was conducted on a sample of soil 15 cm long and 60 cm^2 in cross-sectional area. The quantity of water collected was 50 cm^3 in 20 seconds under a head difference of 24 cm. Calculate the hydraulic conductivity in cm/s. a.1.0 x 10^-1 b.4.3 x 10^-3 c.2.6 x 10^-6 d.3.47 x 10^-2
A constant-head test was conducted on a sample of soil 15 cm long and 60 cm^2 in cross-sectional area. The quantity of water collected was 50 cm^3 in 20 seconds under a head difference of 24 cm. Estimate the hydraulic conductivity in cm/s with a porosity of 35% from the result of test. a.2.6 x 10^-6 b.4.3 x 10^-3 c.7.0 x 10^-6 d.3.47 x 10^-2
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/ 2.8 If the specific weight of a sludge can be expressed as gamma(y) = 10200 + 105h, determine the pressure in N/m^2 at a depth of 4.5 m below the surface. Gamma(y) is in N/m^3 , and h in m below surface
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Refer to the constant-head arrangement shown in Figure 7.5. For a test, the following are given: L = 450 mm A = area of the specimen = 23 cm² %3D Constant-head difference = h = 700 mm Water collected in 3 min = 350 cm³ %3D Calculate the hydraulic conductivity (cm/s).