AirU = 600 m/minP3= 100 kPaT3 = 27°CR-134aP = 1 MPaT = 90°CP = 95 kPaT= 60°CP2= 1 MPaT2= 30°CRefrigerant-134a at 1 MPa and 90°C is to be cooled to 1 MPa and 30°C in a condenser by air. The air enters at 100 kPa and 27°C with a volumeflow rate of 600 m2/min and leaves at 95 kPa and 60°C. Determine the mass flow rate of the refrigerant.O Ay 10 kg/minO B) 25 kg/minC)50 kg/minOPI75 kginminOE) 100 kg min

Answered: Image /qna-images/answer/6da6fc6a-5066-4cc9-8fe8-90a0ea759b94.jpg

Refrigerant-134a at 1 MPa and 90°C is to be cooled to 1 MPa and 30°C in a condenser by air. The air enters at 100 kPa and 27°C with a volum flow rate of 600 mmin and leaves at 95 kPa and 60°C. Determine the mass flow rate of the refrigerant.

Refrigerant-134a at 1 MPa and 90°C is to be cooled to 1 MPa and 30°C in a condenser by air. The air enters at 100 kPa and 27°C with a volum flow rate of 600 mmin and leaves at 95 kPa and 60°C. Determine the mass flow rate of the refrigerant.

Refrigeration and Air Conditioning Technology (MindTap Course List)

8th Edition

ISBN:9781305578296

Author:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson

Publisher:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson

Chapter28: Special Refrigeration Applications

Section: Chapter Questions

Problem 15RQ: Why is two-stage compression popular for extra-low-temperature refrigeration systems?

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Question

Air
U = 600 m/min
P3= 100 kPa
T3 = 27°C
R-134a
P = 1 MPa
T = 90°C
P = 95 kPa
T= 60°C
P2= 1 MPa
T2= 30°C
Refrigerant-134a at 1 MPa and 90°C is to be cooled to 1 MPa and 30°C in a condenser by air. The air enters at 100 kPa and 27°C with a volume
flow rate of 600 m2/min and leaves at 95 kPa and 60°C. Determine the mass flow rate of the refrigerant.
O Ay 10 kg/min
O B) 25 kg/min
C)50 kg/min
OPI75 kginmin
OE) 100 kg min

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