[Relating Coulomb's Law, Gauss's Law and Electric Potential]. (a) Using Gauss's Law find the electric field of a coaxial cylinder with radius a (inner most), in between, and in b (outermost) with length 1 where we treat the charge distribution to be a volume charge distribution (Answer: innermost
[Relating Coulomb's Law, Gauss's Law and Electric Potential]. (a) Using Gauss's Law find the electric field of a coaxial cylinder with radius a (inner most), in between, and in b (outermost) with length 1 where we treat the charge distribution to be a volume charge distribution (Answer: innermost
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![6. Problem Solving Part
Problem
- Integrative
[Relating Coulomb's Law, Gauss's Law and Electric Potential]. (a)
Using Gauss's Law find the electric field of a coaxial cylinder with
radius a (inner most), in between, and in b (outermost) with length 1
where we treat the charge distribution to be a volume charge
distribution (Answer: innermost
pr
ρατ
E = ·↑
20", middle, 2€or
outermostĚ). (b) What is the force if we place a
2
charge q at radius R of
the coaxial cylinder? Hint: This is just a direct substitution. Find the
potential using the equation, V=-SE dl. Hint you can set the limits
of integration from 0 to a. Answer:
V = -5
ραζ
4€0
(1+2ln(
In (-))
0=
l
E =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F18afe7c9-02ee-4ee3-898b-69e973393021%2F440e1d94-3ac8-431d-a306-5e2a1fc69671%2Fn57h30w_processed.jpeg&w=3840&q=75)
Transcribed Image Text:6. Problem Solving Part
Problem
- Integrative
[Relating Coulomb's Law, Gauss's Law and Electric Potential]. (a)
Using Gauss's Law find the electric field of a coaxial cylinder with
radius a (inner most), in between, and in b (outermost) with length 1
where we treat the charge distribution to be a volume charge
distribution (Answer: innermost
pr
ρατ
E = ·↑
20", middle, 2€or
outermostĚ). (b) What is the force if we place a
2
charge q at radius R of
the coaxial cylinder? Hint: This is just a direct substitution. Find the
potential using the equation, V=-SE dl. Hint you can set the limits
of integration from 0 to a. Answer:
V = -5
ραζ
4€0
(1+2ln(
In (-))
0=
l
E =
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