Relative Concentration of Tea Extracts % Inhibition 0.25 0.974 0.5 0.967 0.75 0.965 1.5 0.959 0.25 0.858 0.5 0.976 0.75 0.982 1.5 0.969 0.25 0.974 plot the graph
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|
Relative Concentration of Tea Extracts |
% Inhibition |
|
0.25 |
0.974 |
|
0.5 |
0.967 |
|
0.75 |
0.965 |
|
1.5 |
0.959 |
|
0.25 |
0.858 |
|
0.5 |
0.976 |
|
0.75 |
0.982 |
|
1.5 |
0.969 |
|
0.25 |
0.974 |
plot the graph
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- Sample Relative Concentration of Tea Extracts % Inhibition Green Tea ( 0.25 mg ) 0.25 0.974 Green Tea ( 0.5 mg ) 0.5 0.967 Green Tea ( 0.75 mg ) 0.75 0.965 Green Tea ( 1.5 mg ) 1.5 0.959 Back tea ( 0.25 mg ) 0.25 0.858 Black tea ( 0.5 mg ) 0.5 0.976 Back tea ( 0.75 mg ) 0.75 0.982 Black tea ( 1.5 mg ) 1.5 0.969 plot the graphKm value should be more than 10% apart, use non-competitive inhibitorAn area of application for serial dilution is in Pharmacology when the Minimum Inhibitory Concentration (MIC) of a drug needs to be determined. Research on the MIC and explain how this is related to the serial dilution. Explain your answer. Is there an actual theoretical value for optimum growth temperature? Why or why not? Justify your answer
- please very soon full explanation. You are applying a 15-inch band of herbicide over 30-inch soybean rows and have 10 acres of soybeans left to spray. Your sprayer is calibrated at 15 gpa and the herbicide application rate is 2 qts/ac. How many quarts of herbicide are needed to complete the application?What is the effect of sugar in jelly and jam production. Provide a good refences.Briefly explain why the 14C/12C ratio will decrease after the death of plants. A three- to four-sentence explanation is needed.
- The glucose content of samples can be determined using Nelson't test. The equation of the line for the standard curve preapred for varying concentrations of glucose is y = 3.0x + 0.2. Based from this information, determine the glucose concentration (in M) of a strawberry preserve having an absorbance reading of 1.35.For competitive inhibition: a. the value of Km decreases b. the value of Vmax decreases c. it is possible to overcome the effect of the inhibitor by increasing the concentration of substrate d. none of the aboveCalculate KI' of the inhibitor from the information given. All information may not be needed to calculate. K'm = (29Ki+1.45x10^-10)/Ki Vmax = 11.7 µMs-1 Kcat = 130 s^-1 Vo = 3.0 μMs-1 S = 10 μM Et = 0.09 µM Inhibitor Concentration = 5x10^-12
- After performing surface sterilisation on leaves, the leaf explants were cultured on a medium without supplemented with plant growth regulator. Predict THREE possible observations after a week of culture with justifications.At equivalence point in a precipitation titration of Br- with AgNO3, pAg _____ pBr. Group of answer choices > < =pest control of a yoghurt plant •Identify possible entry point/methods where rats could have gained entry into your production facility •Suggest solutions and follow-up measures to ensure your processing plant is sanitary/safe enough to continue production