Remark 2: Note that there can be several fields of order p". However, they will all be isomorphic, not equal. For example, you can check that x² +1 and x²-x-1 are both irreducible over F3. Hence K= F₂[x] B₂(x)/(x² + 1) ' L=F₂[x] and (x²-x-1) are both fields having 9 elements. Hence both are how do we get this isomorphic to F,. But KL, since, for example, x² +1=0 in K, but x² +1=x+2+0 in L.

Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter8: Polynomials
Section8.6: Algebraic Extensions Of A Field
Problem 6E: In Exercises , a field , a polynomial over , and an element of the field obtained by adjoining a...
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Remark 2: Note that there can be several fields of order p". However, they
will all be isomorphic, not equal. For example, you can check that x² +1 and
_F,[x]/
B₂(x)/(x² + 1)
and
x²-x-1 are both irreducible over F. Hence K =
L= F₂[x]/
5(x ) (x²-x-1) are both fields having 9 elements. Hence both are
how do we get this
2
isomorphic to F. But KL, since, for example, x² +1=0 in K, but
x²+1=x+2+Ō in L.
Transcribed Image Text:Remark 2: Note that there can be several fields of order p". However, they will all be isomorphic, not equal. For example, you can check that x² +1 and _F,[x]/ B₂(x)/(x² + 1) and x²-x-1 are both irreducible over F. Hence K = L= F₂[x]/ 5(x ) (x²-x-1) are both fields having 9 elements. Hence both are how do we get this 2 isomorphic to F. But KL, since, for example, x² +1=0 in K, but x²+1=x+2+Ō in L.
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