Required informationA helical coil compression spring is needed for food service machinery. The load variesfrom a minimum of Fmin 4 lbf to a maximum of Fmax 16 lbf. The spring rate k is to be 9.5Ibf/in. The outside diameter of the spring cannot exceed 2.5 in. The spring maker hasavailable suitable dies for drawing 0.08-in-diameter wire. Use a fatigue design factor nfof 1.5 and the Gerber-Zimmerli fatigue-failure criterion.NOTE: This is a multi-part question. Once an answer is submitted, you will be unable toreturn to this part.Determine the values for each of the following for a value of 0.08 in:The torsional modulus of rupture, Ssu, iskpsi.Torsional yield strength, Ssy, is |kpsi.The endurance strength, assuming unpeened spring wire, Sse, isThe value of the mean diameter, D, isin.The alternating shear stress, Ta, isThe fatigue factor of safety, nf, isThe free length, Lo, isThe critical length, LO(cr), isin.in.kpsi.kpsi.

helical coilExplanation:Step 1:Step 2:Step 3:Step 4:

Answered: Required information A helical coil…

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter2: Axially Loaded Members

Section: Chapter Questions

Problem 2.2.11P: A small lab scale has a rigid L-shaped frame ABC consisting of a horizontal arm AB (length b = 10...

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A helical compression spring is 1o exert a force of 8.0 Ib when compressed 1o a length of 1.75 in. At a length of 1.25 in, the force must be 12.0 Ib. The spring will be installed in a machine that cycles slowly. and approximately 200 000 cycles total are expected. The tem- perature will not exceed 200°F. The spring will be installed in a hole having a diameter of 0.75 in. For this application. specify a suitable material, wire diameter. mean diameter. OD. ID. free length, solid length. number of coils, and type of end condition. Check the stress at the maximum operating load and at the solid length condition. The first of two solution procedures will be shown. The numbered steps can be used as a guide for future problems and as a Kind of algorithm for the spreadsheet approach that follows the manual solution.
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A bushed pin type flexible coupling is used to transmit 10 kW power at 720 rpm. The design torque is 150% of rated torque. The keys have square cross-section. The permissible stresses are: For shaft and key material, τ = 66.67 N/mm2, σc = 200 N/mm2; For pin material, τ = 35 N/mm2, σt = 133 N/mm2; For flange material τ = 16.67 N/mm2. The permissible bearing pressure for rubber bushes is 1 N/mm2. The number of bushes is 4. Design the bushed pin flexible coupling.

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