Homework Help is Here – Start Your Trial Now!
Engineering
Computer Engineering
Restructure Newton's method (Case Study: Approximating Square Roots) by decomposing it into three cooperating functions: newton , limitReached , and improveEstimate.

Restructure Newton's method (Case Study: Approximating Square Roots) by decomposing it into three cooperating functions: newton , limitReached , and improveEstimate.

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
See similar textbooks
icon
Related questions
Question

The question and code are both attatched as images. 

Please only modify the already existing code to do what the question asked it. 

 

Python

 

Thanks!

Restructure Newton's method (Case Study: Approximating Square Roots) by decomposing it into three cooperating functions: newton , limitReached , and improveEstimate. The newton function can use either the recursive strategy of Project 2 or the iterative strategy of the Approximating Square Roots Case Study. The task of testing for the limit is assigned to a function named limitReached , whereas the task of computing a new approximation is assigned to a function named improveEstimate . Each function expects the relevant arguments and returns an appropriate value. An example of the program input and output is shown below: Enter a positive number or enter/return to quit: 2 The program's estimate is 1.4142135623746899 Python's estimate is 1.4142135623730951 Enter a positive number or enter/return to quit
Transcribed Image Text:Restructure Newton's method (Case Study: Approximating Square Roots) by decomposing it into three cooperating functions: newton , limitReached , and improveEstimate. The newton function can use either the recursive strategy of Project 2 or the iterative strategy of the Approximating Square Roots Case Study. The task of testing for the limit is assigned to a function named limitReached , whereas the task of computing a new approximation is assigned to a function named improveEstimate . Each function expects the relevant arguments and returns an appropriate value. An example of the program input and output is shown below: Enter a positive number or enter/return to quit: 2 The program's estimate is 1.4142135623746899 Python's estimate is 1.4142135623730951 Enter a positive number or enter/return to quit
1 # Modify the code below 3 Program: newton.py 4 Author: Ken 5 Compute the square root of a number. 6 1. The input is a number. 7 2. The outputs are the program's estimate of the square root using Newton's method of successive approximations, and Python's own estimate using math.sqrt. 8. 11 12 import math 13 14 # Receive the input number from the user float(input("Enter a positive number: ")) |15 x = 16 17 # Initialize the tolerance and estimate 18 tolerance = 0.000001 19 estimate = 1.0 20 21 # Perform the successive approximations 22 while True: estimate = (estimate + x / estimate) / 2 difference = abs(x - estimate ** 2) if difference <= tolerance: break 23 24 25 26 27 28 # Output the result 29 print("The program's estimate is", estimate) 30 print("Python's estimate is ', math.sqrt(x)) 31
Transcribed Image Text:1 # Modify the code below 3 Program: newton.py 4 Author: Ken 5 Compute the square root of a number. 6 1. The input is a number. 7 2. The outputs are the program's estimate of the square root using Newton's method of successive approximations, and Python's own estimate using math.sqrt. 8. 11 12 import math 13 14 # Receive the input number from the user float(input("Enter a positive number: ")) |15 x = 16 17 # Initialize the tolerance and estimate 18 tolerance = 0.000001 19 estimate = 1.0 20 21 # Perform the successive approximations 22 while True: estimate = (estimate + x / estimate) / 2 difference = abs(x - estimate ** 2) if difference <= tolerance: break 23 24 25 26 27 28 # Output the result 29 print("The program's estimate is", estimate) 30 print("Python's estimate is ', math.sqrt(x)) 31
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Recommended textbooks for you
Computer Networking: A Top-Down Approach (7th Edi…
Computer Networking: A Top-Down Approach (7th Edi…
Computer Engineering
ISBN:
9780133594140
Author:
James Kurose, Keith Ross
Publisher:
PEARSON
Computer Organization and Design MIPS Edition, Fi…
Computer Organization and Design MIPS Edition, Fi…
Computer Engineering
ISBN:
9780124077263
Author:
David A. Patterson, John L. Hennessy
Publisher:
Elsevier Science
Network+ Guide to Networks (MindTap Course List)
Network+ Guide to Networks (MindTap Course List)
Computer Engineering
ISBN:
9781337569330
Author:
Jill West, Tamara Dean, Jean Andrews
Publisher:
Cengage Learning
Concepts of Database Management
Concepts of Database Management
Computer Engineering
ISBN:
9781337093422
Author:
Joy L. Starks, Philip J. Pratt, Mary Z. Last
Publisher:
Cengage Learning
Prelude to Programming
Prelude to Programming
Computer Engineering
ISBN:
9780133750423
Author:
VENIT, Stewart
Publisher:
Pearson Education
Sc Business Data Communications and Networking, T…
Sc Business Data Communications and Networking, T…
Computer Engineering
ISBN:
9781119368830
Author:
FITZGERALD
Publisher:
WILEY
SEE MORE TEXTBOOKS