* Returns a new string with s2 inserted in the middle of string sl * for example, insertInMiddle ("abcd", "wxyz") returns "abwxyzcd" * If there are an odd number of characters in s1, then split s1 so the middle * character comes after s2, so * insertInMiddle ("abc", "wxyz") returns "awxyzbc" public static String insertInMiddle (String s1, String s2) { return "This the wrong string"; }

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Complete the method in Java. Name of the public class is Assignment1.java

}
* Returns a new string with s2 inserted in the middle of string s1
* for example, insertInMiddle ("abcd", "wxyz") returns "abwxyzcd"
* insertInMiddle ("abc", "wxyz") returns "awxyzbc"
*/
public static String insertInMiddle (String s1, String s2) {
return "This the wrong string";
* If there are an odd number of characters in sl, then split s1 so the middle
* character comes after s2, so
}
public static void main(String[] args) {
if (!insertInMiddle("abcd","wxyz").equals("abwxyzcd")) {
System.out.println("Failed on case abwxyzcd");
String testme;
testme = "awxyzbc";
if (!insertInMiddle ("abc", "wxyz").equals (testme)) {
System.out.println("Failed on case " + testme);
}
System.out.println("Test completed");
Transcribed Image Text:} * Returns a new string with s2 inserted in the middle of string s1 * for example, insertInMiddle ("abcd", "wxyz") returns "abwxyzcd" * insertInMiddle ("abc", "wxyz") returns "awxyzbc" */ public static String insertInMiddle (String s1, String s2) { return "This the wrong string"; * If there are an odd number of characters in sl, then split s1 so the middle * character comes after s2, so } public static void main(String[] args) { if (!insertInMiddle("abcd","wxyz").equals("abwxyzcd")) { System.out.println("Failed on case abwxyzcd"); String testme; testme = "awxyzbc"; if (!insertInMiddle ("abc", "wxyz").equals (testme)) { System.out.println("Failed on case " + testme); } System.out.println("Test completed");
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