Returns the area of the largest rectangle whose top left corner is at position , in . You MUST make use of the helper here as you loop through each row of the matrix. Do not modify (i.e., mutate) the input matrix.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Can you please show me the code for the second question, the largest-at-position one?

def longest_chain(lst: list[int]) -> int:
Your longest_chain function from last week, make sure this works properly
before proceeding with the rest of the lab!
max = 0
Lis
counts = 0
while Lis < len(lst):
if lst[Lis]
1:
==
counts += 1
else:
if counts > max:
max = counts
Counts = 0
Lis += 1
if counts > max:
max= counts
return max
def largest at_position(matrix: list[list[int]], row: int, col: int) -> int:
Returns the area of the largest rectangle whose top left corner is at
position <row>, <col> in <matrix>.
You MUST make use of the helper <Longest_chain> here as you loop through
each row of the matrix. Do not modify (i.e., mutate) the input matrix.
>>> case1 = [[1, 0, 1, 0, 0],
[1, 0, 1, 1, 1],
[1, 1, 1, 1, 1],
[1, 0, 0, 1, 0]]
>>> largest_at_position(case1, 0, 0)
4
>>> largest_at_position(case1, 2, 0)
>>> largest_at_position(case1, 1, 2)
6
Transcribed Image Text:def longest_chain(lst: list[int]) -> int: Your longest_chain function from last week, make sure this works properly before proceeding with the rest of the lab! max = 0 Lis counts = 0 while Lis < len(lst): if lst[Lis] 1: == counts += 1 else: if counts > max: max = counts Counts = 0 Lis += 1 if counts > max: max= counts return max def largest at_position(matrix: list[list[int]], row: int, col: int) -> int: Returns the area of the largest rectangle whose top left corner is at position <row>, <col> in <matrix>. You MUST make use of the helper <Longest_chain> here as you loop through each row of the matrix. Do not modify (i.e., mutate) the input matrix. >>> case1 = [[1, 0, 1, 0, 0], [1, 0, 1, 1, 1], [1, 1, 1, 1, 1], [1, 0, 0, 1, 0]] >>> largest_at_position(case1, 0, 0) 4 >>> largest_at_position(case1, 2, 0) >>> largest_at_position(case1, 1, 2) 6
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