Rewrite the following code using one if-else statement If (aChar ==’A’) c++; if (aChar !=’A’) printf (“value is A\n);
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- Rewrite the following code using one if-else statement
If (aChar ==’A’)
c++;
if (aChar !=’A’)
printf (“value is A\n);
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- (Numerical) a. Write a C++ program that accepts an integer argument and determines whether the passed integer is even or odd. (Hint: Use the % operator.) b. Enter, compile, and run the program written for Exercise 8a.Look at the following C++ code: for(i=1; i<=12;i++) { for(j=1;j<=(i/3); j++) { cout<<j<<" "; } cout<<endl; } Mention the output. Also put the value of i and j in each line.Answer the following questions 1. Rewrite the following code using one if-else statement If (aChar ==’A’) c++; if (aChar !=’A’) printf (“value is A\n); Answer:
- Write a C statement to accomplish each of the following tasks.c) Set variable sum to 0.Write c code to check if it is possible to devide number by 5 and 6 both Take number from user and if number is can be devided by 5 and 6 then print it is devisable otherwise print not devisableWrite C++ statements that will: Print a quotient and remainder of 19 / 14.
- Q: Rewrite the following code fragment so that a MULTI-WAY IF/ELSE is USED instead of the switch statement. * use C++ programWrite a single C++ statement that will: Print the ASCII integer value of the variable: char c = ‘K’Name all the errors in the following code: c++ #include <iostream>int main() { int x = 1; int total; while (x < 5) { total = 2 + x; if (x > 3); break; } cout << "Total= << total << endl }