Re(z) dz, where C is the right half circle |2| = 3, from z 2² – 2i (Ъ) -3i to z = 3i.

Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter8: Conic Sections
Section8.2: More Parabolas And Some Circles
Problem 63.2PS: By expanding (xh)2+(yk)2=r2, we obtain x22hx+h22ky+k2r2=0. When we compare this result to the form...
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Solve (b)
2. Find an upper bound of the absolute value of the integral
ez + 1
(a)
-dz, where C is the right half circle |2| = 3, from z = -3i to z = 3i.
2z2 + 1
C
Re(z)
2
-dz, where C is the right half circle |z| = 3, from z = -3i to z = 3i.
2i
(b)
C
(0) [te²-
- Im(2))dz, where C is the line segment from z = 0 to z = 2+ 2i.
Transcribed Image Text:2. Find an upper bound of the absolute value of the integral ez + 1 (a) -dz, where C is the right half circle |2| = 3, from z = -3i to z = 3i. 2z2 + 1 C Re(z) 2 -dz, where C is the right half circle |z| = 3, from z = -3i to z = 3i. 2i (b) C (0) [te²- - Im(2))dz, where C is the line segment from z = 0 to z = 2+ 2i.
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