Verify that 1, is an eigenvalue of A and that x; is a corresponding eigenvector.11 = -11, x1 = (1, 2, –1)12 = -3, x2 = (-2, 1 0)13 = -3, x3 = (3, 0, 1)-4 -2A =-2 -76.12-6-4 -231AX 12 = 1,x1-2 -76.21112 -6-1-1-4 -2-2-2Ax2-2 -71= -3112 -6-4 -2Ax3 =-2 -76.-3= 13×32 -61m O LO

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rify that 2, is an eigenvalue of A and that x, is a corresponding eigenvector. а13 -11, х, 3 (1, 2, -1) 6, 12 = -3, x, = (-2, 1 0) d3 = -3, x3 = (3, 0, 1) -4 -2 3 A = -2 -7 1 2 -6 -4 -2 3 1 -2 -7 6 2 = -11 2 = 1,x1 %3D 1 2 -6 -1 - -4 -2 3 -2 -2 2 = -2 -7 6 1 = -3 = 12x2 2 -6 JL -- E -4 -2 3 = -2 -7 -3 = 13×3 1 2 -6 11

rify that 2, is an eigenvalue of A and that x, is a corresponding eigenvector. а13 -11, х, 3 (1, 2, -1) 6, 12 = -3, x, = (-2, 1 0) d3 = -3, x3 = (3, 0, 1) -4 -2 3 A = -2 -7 1 2 -6 -4 -2 3 1 -2 -7 6 2 = -11 2 = 1,x1 %3D 1 2 -6 -1 - -4 -2 3 -2 -2 2 = -2 -7 6 1 = -3 = 12x2 2 -6 JL -- E -4 -2 3 = -2 -7 -3 = 13×3 1 2 -6 11

Elementary Linear Algebra (MindTap Course List)

8th Edition

ISBN:9781305658004

Author:Ron Larson

Publisher:Ron Larson

Chapter7: Eigenvalues And Eigenvectors

Section7.1: Eigenvalues And Eigenvectors

Problem 76E: Define T:P2P2 by T(a0+a1x+a2x2)=(2a0+a1a2)+(a1+2a2)xa2x2. Find the eigenvalues and the eigenvectors...

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