A 245-kg merry-go-round in the shape of a uniform, solid, horizontal disk of radius 1.50 m is set in motion by wrapping a rope about the rim of the disk and pulling on the rope. What constant force would have to be exerted on the rope to bring the merry-go-round from rest to an angular speed of 0.600 rev/s in 2.00 s? (State the magnitude of the force.)A torque of 37.1 N. m is applied to an initially motionless wheel which rotates around a fixed axis. This torque is the result of a directed force combined with a friction force. As a result of the applied torque the angular speed of the wheel increases from 0 to 9.9 rad/s. After 5.80 s the directed force is removed, and the wheel comes to rest 59.4 s later.(a) What is the wheel's momentinertia (in kg · m?kg · m2(b) What is the magnitude of the torque caused by friction (in N. m)?N. m(c) From the time the directed force is initially applied, how many revolutions does the wheel go through?revolutions

Dear student as you have asked multiple question, according to Bartleby policy we can solve only 1st…

-round in the shape of a uniform, solid, horizontal disk of radius 1.50 m is set in motion by wrapping a rope about the rim of the disk and pulling on the rope. What constant force would have to be exerted on the rope to bring the merry-go-round from rest to an angular speed of 0.600 rew/s in 2.00 s? (State the magnitude of the force.)

-round in the shape of a uniform, solid, horizontal disk of radius 1.50 m is set in motion by wrapping a rope about the rim of the disk and pulling on the rope. What constant force would have to be exerted on the rope to bring the merry-go-round from rest to an angular speed of 0.600 rew/s in 2.00 s? (State the magnitude of the force.)