R(p) = 600p - 6p^2 maximum revenue is 15,000 how many units are sold at this price?
R(p) = 600p - 6p^2 maximum revenue is 15,000 how many units are sold at this price?
Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter10: Exponential And Logarithmic Functions
Section10.2: Applications Of Exponential Functions
Problem 47PS
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R(p) = 600p - 6p^2
maximum revenue is 15,000
how many units are sold at this price?
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