S cos(2x)e2* dx (recurring)

Q: 3.3 Inx + tanxe d 4-4x -sinte dx

A:

Q: 3 cos(x)³ dx

A: We need to evaluate integral.

Q: Evaluate

A: ∫3cos22x dx factor out the constant term outside integral symbol. ∫3cos22xdx =3∫1cos22xdx=3∫sec22xdx…

Q: tan(e-2x) In(cos(e-2*)) dx 5 S е 2х

A: We have to find out

Q: 2x -1 If y-f and .1 + 'א. dy f'(x) - sinx".find - dx

A: NOTE: Refresh your page if you can't see any equations. . now substitute

Q: π/2 cos² x dx

A: This question can be solved using the concept of properties of definite integrals.

Q: dly dx2 - 2 dy dx -3y = COS X

A: The given differential equation is d2ydx2-2dydx-3y=cosx. We have to find the solution of the given…

Q: 2cosx dx 2 5- fn 1+(sinx)? π

A:

Q: S cos(2x)e2x dx

A: We need to evaluate: ∫cos(2x)e2xdx

Q: find Dxy if y=e^(-2/x^2) Dxy=?

A:

Q: S+ xcos (nx) dx + (π-x)(cos(nx)) dx

A: Here we will use integration by parts  let f(x) and g(x) are two function of x then…

Q: 3.fe²x cos 3x dx

A: The given integral is ∫e2xcos 3xdx Integrate by parts  where first function is e2x and second…

Q: (2x-ィ) cos 3x dx

A: The given function is, ∫(2x2-1) cos3x dx. Obtain the value of the integral ∫(2x2-1) cos3x dx.…

Q: 14. S4 cos (-3x + 2) dx

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Q: c- S cos(Inx).dx

A:

Q: S cos 4x cos 3x dx

A: We need to evaluate integral.

Q: e3 sin(5x) dx %3D

A:

Q: L(cos at) = s2 - a2

A: To verify that ℒcos at=ss2-a2.

Q: [(1+cos 3x) dx 3x)?dx + cos

A: Given: I=∫(1+cos(3x))32dx

Q: S sin5x cos³x dx

A: Given∫sin5xcos3xdx

Q: S cos³ 3x dx со

A:

Q: | e3* sin(2x)dx

A:

Q: Cos^3(3x) dx

A:

Q: S cos 2x dx COSX

A:

Q: S cos(7x) cos (18x)dx

A:

Q: fxcos (x)dx COS

A: Assume u=x^2Find du

Q: S cos" (3x) dx CoS

A: Apply integration by parts

Q: 3x Cos 2x dx

A: Simple use integration by parts method.

Q: (一 - dx t - 3 X*cos(3)-4-2 ) -)dy=0 = 0

A:

Q: 3) cos-1x. dx

A:

Q: S sin³ (2x)cos² (2x)dx

A:

Q: x° cos (3x) dx X COS

A: Integral by parts:∫ uv dx =u∫ vdx -∫(dudx∫vdx) dxI=∫ x6 cos(3x) dxu=x6, dudx=6x5v=cos(3x), ∫ vdx…

Q: dx 2x2+8 dx -9x2+6x-2 e2X sin(e2x)dx cos? (e2x)+3

A:

Q: S cos²(2x)dx

A:

Q: dx = 3 cos° x/2sinx

A:

Q: S tan-1(bx) dx

A:

Q: f Cos 6 x dx 2 Cos ²3x

A: Solving the problem by finding the value of the problem.

Q: S cos³ 3x dx

A:

Q: 2. cos x dx - 67

A:

Q: – (x²- 1) dx using P (1 -;*)-^;* / * m in terms of A?

A: Use simple integration formula.

Q: a²-x2 6- Sº, S dy dx -Va2-x2 7- Sx? cos 5 x dx

A: As per bartelby guidelines we have permitted answer only one question if given more than one…

Q: (6secx cos x dx :

A: Put secx = 1/cos(x)

Q: dx 1.f- 1+cosh x

A:

Q: dx 2x2+8 dx -9x2+6x-2 e 2X sin(e2x)dx cos²(e2x)+3

A:

Q: dx 5+4 cos x

A:

Q: dx 9. 2- cos X

A: To evaluate :

Q: 5x cos dx 2 x3 cos 9x dx X' COS

A:

Q: S cos(2x)e2× dx

A: