dx√√2/2/2+ x= x ¹/²2; 2 √ =—=1 / 2²+1/4: 4√√2-1+Consider(A)Bz = x ¹/4;C) none of the choices(D)z = x ¹/4; 4(ΕEZ = XZ=Using rationalizing substitution, what will be z and its corresponding integral?dzz+1Z√ √ ² ²1 + 2'x ¹/², 2/———2 d²dz1+zdzdz

Answered: Image /qna-images/answer/6cc2c21c-5981-4117-8b70-02c75c6b1d90.jpg

S dx . Consider ½/₂ Using rationalizing substitution, what will be z and its corresponding integral? + x 1/2₁ 1 x ¹/²2; 2 √ ——²/2 A z = x dz 1+z² ℗ 2 - x 1/4; + √(2-1 + 2 + 1)^²= B |z= 4 1+ dz z+1 none of the choices |z= x¹/4; 4 = 22 di dz ℗ 2 = x ¹/²2; 2 √ √ + 1/² d² dz 1+2

S dx . Consider ½/₂ Using rationalizing substitution, what will be z and its corresponding integral? + x 1/2₁ 1 x ¹/²2; 2 √ ——²/2 A z = x dz 1+z² ℗ 2 - x 1/4; + √(2-1 + 2 + 1)^²= B |z= 4 1+ dz z+1 none of the choices |z= x¹/4; 4 = 22 di dz ℗ 2 = x ¹/²2; 2 √ √ + 1/² d² dz 1+2

Elements Of Modern Algebra

8th Edition

ISBN:9781285463230

Author:Gilbert, Linda, Jimmie

Publisher:Gilbert, Linda, Jimmie

Chapter5: Rings, Integral Domains, And Fields

Section5.4: Ordered Integral Domains

Problem 5E: 5. Prove that the equation has no solution in an ordered integral domain.

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