·S- For x 1/2 dx and using the substitution=x1/2, the resulting integral takes t U -du 1-u² 4u 4-4² 4u S- U -du (2u2) 2 -du -u4 -du

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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QUESTION 11
·[.
x1/2
For
-dx and using the substitution
-du
-du
U
4u
4-4²
4u
4-(24²) ²
U
-du
S-
- u4
-du
u=x 1/2, the resulting integral takes the form:
Transcribed Image Text:QUESTION 11 ·[. x1/2 For -dx and using the substitution -du -du U 4u 4-4² 4u 4-(24²) ² U -du S- - u4 -du u=x 1/2, the resulting integral takes the form:
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