S x2 +2x-10 (2x+4) + 1 JE + 4x +5) Consider dx = x² (x² + 4x + 5) (2x+4) + 1 dx- x² + 4x +5 dx , evaluate x2 2Inx + -- In(x² + 4x +5)– Arctan(x +2) + C 2 - In(x2 + 4x+5) + Arctan(x+ 2) +C 2Inx + 2 2Inx – In(x2 + 4x +5) – Arctan(x + 2) + C 2 2lnx - In(x2 + 4x + 5)+ Arctan(x +2) + C

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