seat sinc(t) dt

Q: (3 csc² t - 5 sec t tan t) dt

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Q: S sinx cosx dx

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Q: Cosx dx

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Q: + cosx dx = ?

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Q: dx = cosx cos²t dt

A: dxdt=cosx cos2t On simplification, we get dxcosx=cos2t dt

Q: y=(sinx)cosx

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Q: d -cot -1 dx du 1+ и? dx U = -

A:

Q: ∫e^cosx sinxdx

A: To find the integral of, ∫ecosx sinx dx

Q: S(Sinx +CoSX) 人×

A: Solution: The objective is to find the value of the given integral

Q: d/dx sin x

A: d/dx sin(x)

Q: cos° (nt)dt

A:

Q: sin' x dx = (b) O b O e NIM

A: Given,∫0π2sin3 x dx

Q: Scotx dx sin 2x cos' 2x dx g. i

A: To evaluate the given integrals by substitution method.

Q: x Arctan(x?) dx

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Q: V1+cos.x dx = ?

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Q: L{e-(sint + cosht}

A: As per our guidelines, we are supposed to solve only first question. Kindly repost other question as…

Q: dx A. 1+cosx

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Q: Sint dt ds く ーb ヒニb

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Q: dy/dx of pi

A: pi is a constant.It has value 3.14 approx.

Q: g dx dg sin f

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Q: sin x 31 dt dx

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Q: dx sinx

A: I=∫exsinxdxBy using integration by…

Q: sin x dx J

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Q: f(t) = sin t

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Q: dx i-Sin X

A: Given integral is ∫π4π311-sinxdx

Q: sint dt Evaluate

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Q: sin(0) d0 T/3

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Q: Jx sinx cosx dx

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Q: (c) cos-(VI+1) dx

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Q: y = sec- (Arcsec (V) + e %3D

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Q: Sx sin 'a dx

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Q: y = sinx, x=0, and y= /4

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Q: Cos A dx =0 ulgn

A: The given integral is                                      ∫-LLcos nπxLdx

Q: dx Arcsin (²) + c

A:

Q: (y - sinx)dx + xdy = 0 %3D

A: The given differential equation is  (y - sinx) dx + x dy = 0

Q: dx - COSX

A: Given integral is: ∫11-cosxdx

Q: Cos (Jx) dx

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Q: Find of the equation y = cosx(1+ cscx). dx

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Q: f In dx

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Q: Sx sin? x dx

A: We solve the above problem by using the method of integration by parts.…

Q: | cos x dx ile ( Jcos x| dx

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Q: sin(v3t) (b) L-- [tan- )) (a) L dt

A: In this question, we use the properties of Laplace and inverse Laplace transform, find the Laplace…

Q: (a) / 1 dx, 1- x2

A: As per our guidelines we can answer only 1 question so kindly repost the remaining questions…

Q: te'sint dt

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Q: Evaluate dx using trigonometric substitution. V25- x2

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Q: +cos x dx =?

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Q: csc t sin 3t dt

A: Solve the following

Q: cos3.t dt

A: