note this is all one problem. Second Derivative Test1. Find the first derivative of the function g(x) = 4x° + 6x? – 240x.gʻ(x)2. Find the second derivative of the function.g"(x) =3. Evaluate g"( – 5).g"( – 5) =4. Is the graph of g(x) concave up or concave down at x =5?At x- 5 the graph of g(x) is concave5. Does the graph of g(x) have a local minimum or local maximum at x =– 5?At x =5 there is a local

Answered: Image /qna-images/answer/1d2b3ce6-dc87-4e44-a192-e3dbfe382dcc.jpg

Answered: Second Derivative Test 1. Find the…

Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015

1st Edition

ISBN:9781680331141

Author:HOUGHTON MIFFLIN HARCOURT

Publisher:HOUGHTON MIFFLIN HARCOURT

Chapter8: Graphing Quadratic Functions

Section: Chapter Questions

Problem 17CT

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34 - What is the value of the first derivative of the function at x = 2? A) 2B) 1C) -2/3D) NO derivativeE) 0
shows the graphs of the first and second derivatives of a function y = ƒ(x). Copy the picture and add to it a sketch of the approximate graph of ƒ, given that the graph passes through the point P.
Compute the derivative function f′(a) algebraically for the given value of x.f(x) = −x − x2; a = 0 Find the equation of the tangent to the graph at the indicated point of a = 0 for using the function and information found from Hint: to find a linear equation, we need a slope and a point.
A. Find the slope of the curve y = x² - 2x - 4 at the point (2, -4) by finding the limiting value of the slope of the secant line through the point B. Find the equation of the tangent line to the curve at (2, -4)
Given the function f(x) = 3cos(x/2), find the relative extrema on the interval (pi, 7pi) using the First Derivative Test and the Second Derivative Test. Compare the results. Graph the function with the relative extrema.
Determine the point(s) (if any) at which the graph of the function has a horizontal tangent line. y = √3 x + 2 cos(x), 0 ≤ x < 2? Step1: Find a derivative y'. Step2 : Set y' = 0 and solve for x. x1 = (smaller x-value) x2 = (larger x-value) STEP 3: Find the y values by substituting the values from Step 2 into the original function. y1 corresponds to x1 and y2 corresponds to x2. List the points where the function has horizontal tangent lines. Submit your answers in terms of pi for ?. (x1, y1) = (x2, y2) =
Compute the derivatives of the following functions. Find the value of the function and the slope at 0, π/2, and π.Sketch a graph of the function on the given domain. How would you describe the behavior in words? a(x) = 3x + cos(x) for 0≤x ≤2π.
Use the graph of a function y = f(x) to answer the questions about the derivative: the graphs equation is y=-x^2 +3 Which of the values of x listed is the best estimate for the solution to f'(x) = 0i. x = -1.75ii. x = 0iii. x = 1.75iv. x = 4 Which of the values of x listed below is the best estimate for the solution to f'(x) = −1i. x = -2ii. x = -1/2iii. x = 1/2iv. x = 3
I’m looking for help with 18. How do I apply the definition of a derivative to find the a and function that is represented by this?
Sodium chlorate crystals are easy to grow in the shape of cubes by allowing a solution of water and sodium chlorate to evaporate slowly. If V is the volume of such a cube with side length x, calculate the derivative when x = 5 mm. V'(5) = mm3/mm What does V'(5) mean in this situation? V'(5) represents the rate at which the volume is increasing with respect to the side length as V reaches 15 mm3.V'(5) represents the volume as the side length reaches 5 mm. V'(5) represents the rate at which the volume is increasing as x reaches 15 mm.V'(5) represents the rate at which the side length is increasing with respect to the volume as x reaches 5 mm.V'(5) represents the rate at which the volume is increasing with respect to the side length as x reaches 5 mm.
#14 can you show me how to do this? Our teacher has been using the equation f(x+h)-f(x)/h to find the derivatives.

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