separation of variables to find the solutions to the differential equations in Problems 1-12, ect to the given initial conditions. -=-2P, P(0)=1 dp p. -=1, P(0)=1 N 2. 4. dm ds L == 2 L(0) = 100 -=m, m(1) = 2

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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separation of variables to find the solutions to the differential equations in Problems 1-12,
ect to the given initial conditions.
di
=-2P, P(0)=1
ap
2 du = u², u(0) = 1
dt
dy
dt
dz
=1, P(0)=1
11.
y
3+1
dz
y (0) = 1
= te², through the origin
=z+zt²,
z = 5 when 1 = 0
O O O O
Samsung Quad Camera
Shot with my Galaxy A32
2.
4p
00
dm
4. = m, m(1) = 2
dR
10.
dy_5y
12.
20
2
+R=1, R(1) = 0.1
dy
dy
Z(0) = 100
X
y=3 where x = 1
=(1+), y = 2 when t = 1
z=1 when y=0
B
$
**
Focus
12°C A
0 F
@
Transcribed Image Text:separation of variables to find the solutions to the differential equations in Problems 1-12, ect to the given initial conditions. di =-2P, P(0)=1 ap 2 du = u², u(0) = 1 dt dy dt dz =1, P(0)=1 11. y 3+1 dz y (0) = 1 = te², through the origin =z+zt², z = 5 when 1 = 0 O O O O Samsung Quad Camera Shot with my Galaxy A32 2. 4p 00 dm 4. = m, m(1) = 2 dR 10. dy_5y 12. 20 2 +R=1, R(1) = 0.1 dy dy Z(0) = 100 X y=3 where x = 1 =(1+), y = 2 when t = 1 z=1 when y=0 B $ ** Focus 12°C A 0 F @
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