Set up (but do not integrate) the integral used to find the area between the curves y = 8+4x-x^2y=8+4x−x2 and y=5x+2.y=5x+2. Answer Choices: \displaystyle \int_{-3}^2 (x^2+x-6)dx∫−32​(x2+x−6)dx \displaystyle \int_{-2}^3 (6-x-x^2) dx∫−23​(6−x−x2)dx \displaystyle \int_{-3}^2 (6-x-x^2) dx∫−32​(6−x−x2)dx \displaystyle \int_{-3}^2 (10-x-x^2) dx∫−32​(10−x−x2)dx

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A: Explanation of the answer is as follows

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A: Let's find.