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Set-up the definite integral that will give the measure of surface area of the solid generated 1 by revolving the curve 3y=(x² 6 1.275, 5² √214-9072²-18 Α. 2π x 1+ 3 1-² C. 27 6 3 X 2 1+ dx - dx 2 I from x = 3 to x = 6, about the y-axis. 27f₁ 3 B. 27 x D. 2 2 6 205"> (1+ x 1+ 9x 1 2 x 18 9x²-18 dx dx

Set-up the definite integral that will give the measure of surface area of the solid generated 1 by revolving the curve 3y=(x² 6 1.275, 5² √214-9072²-18 Α. 2π x 1+ 3 1-² C. 27 6 3 X 2 1+ dx - dx 2 I from x = 3 to x = 6, about the y-axis. 27f₁ 3 B. 27 x D. 2 2 6 205"> (1+ x 1+ 9x 1 2 x 18 9x²-18 dx dx

Intermediate Algebra
Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter8: Conic Sections
Section8.2: More Parabolas And Some Circles
Problem 63.2PS: By expanding (xh)2+(yk)2=r2, we obtain x22hx+h22ky+k2r2=0. When we compare this result to the form...
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Set-up the definite integral that will give the measure of surface area of the solid generated 1 by revolving the curve 3y=(x² , from x = 3 to x = 6, about the y-axis. 6 1.275, 57√14-982²-18 Α. 2π x 1+ 3 C. 27 6 3 X 2 1+ 1-² 9x²-2 dx - dx 27f₁ 3 B. 27 x D. 2π 2 6 205"> 1+ x 1+ 9x 1 2 18 9x²-18 dx dx
Transcribed Image Text:Set-up the definite integral that will give the measure of surface area of the solid generated 1 by revolving the curve 3y=(x² , from x = 3 to x = 6, about the y-axis. 6 1.275, 57√14-982²-18 Α. 2π x 1+ 3 C. 27 6 3 X 2 1+ 1-² 9x²-2 dx - dx 27f₁ 3 B. 27 x D. 2π 2 6 205"> 1+ x 1+ 9x 1 2 18 9x²-18 dx dx
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