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Show first that (n – 1)!2 (2n)! Š(2) = 3 n=1 To evaluate the value of the series on the right-hand side, use the Taylor series 1-'(n – 1)!² „2n (2n)! 22n-1(n – 00 arcsin?x = E n=1

Show first that (n – 1)!2 (2n)! Š(2) = 3 n=1 To evaluate the value of the series on the right-hand side, use the Taylor series 1-'(n – 1)!² „2n (2n)! 22n-1(n – 00 arcsin?x = E n=1

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.3: Geometric Sequences
Problem 44E
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Show first that (n – 1)!2 (2n)! 00 3(2) = 3 n=1 To evaluate the value of the series on the right-hand side, use the Taylor series arcsin?x = E 0 22n-1(n – 1)!- 2n. Σ (2n)! n=1
Transcribed Image Text:Show first that (n – 1)!2 (2n)! 00 3(2) = 3 n=1 To evaluate the value of the series on the right-hand side, use the Taylor series arcsin?x = E 0 22n-1(n – 1)!- 2n. Σ (2n)! n=1
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