Show how did the theta have been solved from the two equations and Fcd?
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A: Given : Currrent, I=3.8 A Magnetic flux density= B=14.1 T Angle, θ=210 Length of the wire, l= 20 mm
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Show how did the theta have been solved from the two equations and Fcd?
![Equations of Equilibrium. Referring to Fig. a,
+EF = 0; NA - 200 cos 0 = 0
+/F = 0; FCD +0.25(200 cos ) - 200 sin 0 = 0
Also, by referring to Fig. b,
+ΣFy = 0; NB - 150 cos 0 = 0
+/EF = 0; 0.35(150 cos 0) FCD - 150 sin 0 = 0
Solving Eqs. (1) and (2), yields
-
0
=
16.3°
ΝΑ = 200 cos 0
FCD= 8.23 lb
NB = 150 cos 0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F14d53b6e-6ee5-4816-a6dd-ebd7ead6c112%2Fca554176-5238-47b4-b2c6-1337122771b2%2Fz2tdw7e_processed.jpeg&w=3840&q=75)
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