Show how each of the following floating-point values would be stored using IEEE-754 single precision (be sure to indicate the sign bit, the exponent, and the significand fields): a) 12.5 b) -1.5 c) 0.75 d) 26.625
Show how each of the following floating-point values would be stored using IEEE-754 single precision (be sure to indicate the sign bit, the exponent, and the significand fields): a) 12.5 b) -1.5 c) 0.75 d) 26.625
Chapter8: Data And Network Communication Technology
Section: Chapter Questions
Problem 31VE
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Question
Show how each of the following floating-point values would be stored using IEEE-754 single precision (be sure to indicate the sign bit, the exponent, and the significand fields):
a) 12.5 b) -1.5 c) 0.75 d) 26.625
Expert Solution
Step 1
a)
Converting 12.5 to binary Convert decimal part first, then the fractional part > First convert 12 to binary Divide 12 successively by 2 until the quotient is 0 > 12/2 = 6, remainder is 0 > 6/2 = 3, remainder is 0 > 3/2 = 1, remainder is 1 > 1/2 = 0, remainder is 1 Read remainders from the bottom to top as 1100 So, 12 of decimal is 1100 in binary > Now, Convert 0.5 to binary > Multiply 0.5 with 2. Since 1.0 is >= 1. then add 1 to result > This is equal to 1, so, stop calculating 0.5 of decimal is .1 in binary so, 12.5 in binary is 1100.1 12.5 in simple binary => 1100.1 so, 12.5 in normal binary is 1100.1 => 1.1001 * 2^3 single precision: -------------------- sign bit is 0(+ve) exp bits are (127+3=130) => 10000010 Divide 130 successively by 2 until the quotient is 0 > 130/2 = 65, remainder is 0 > 65/2 = 32, remainder is 1 > 32/2 = 16, remainder is 0 > 16/2 = 8, remainder is 0 > 8/2 = 4, remainder is 0 > 4/2 = 2, remainder is 0 > 2/2 = 1, remainder is 0 > 1/2 = 0, remainder is 1 Read remainders from the bottom to top as 10000010 So, 130 of decimal is 10000010 in binary frac bits are 10010000000000000000000 so, 12.5 in single-precision format is 0 10000010 10010000000000000000000 in hexadecimal it is 0x41480000
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