Show that 1 + 2 Σ ) Σ E 8(z – k) cos 2n7x n=1 k=-00 in the sense of distribution.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section2.1: Equations
Problem 75E
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. Show that
1 + 2 )
cos 2nrx =
E 6(x – k)
|
n=1
k=-0
in the sense of distribution.
Transcribed Image Text:. Show that 1 + 2 ) cos 2nrx = E 6(x – k) | n=1 k=-0 in the sense of distribution.
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