Show that every function f is defined by f(x) = (x³ + c)e-3x where c is an arbitrary constant, is a solution of the differential equation dy + 3y = 3x?e-3x dx

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Show that every function f is defined by
f(x) = (x³ + c)e-3x
where c is an arbitrary constant, is a solution of the differential equation
dy
+ 3y = 3x?e-3x
dx
Show that the function f defined by f(x) = (2x² + 2e3x + 3)e-2X satisfies the differential equation
+ 2y = 6ex + 4xe-2x
dy
And also the condition f(0) = 5
Transcribed Image Text:Show that every function f is defined by f(x) = (x³ + c)e-3x where c is an arbitrary constant, is a solution of the differential equation dy + 3y = 3x?e-3x dx Show that the function f defined by f(x) = (2x² + 2e3x + 3)e-2X satisfies the differential equation + 2y = 6ex + 4xe-2x dy And also the condition f(0) = 5
Given that every solution of
dy
+ y = 2xe-x
dx
may be written in the form y = (x² + c)e¯* , for some choice of arbitrary constant c, solve the following
initial-value problems;
dy
(a)
dx
+y = 2xe-* , y(0) = 2
dy
(b) + y = 2xe* ,y(-1) = e + 3
Transcribed Image Text:Given that every solution of dy + y = 2xe-x dx may be written in the form y = (x² + c)e¯* , for some choice of arbitrary constant c, solve the following initial-value problems; dy (a) dx +y = 2xe-* , y(0) = 2 dy (b) + y = 2xe* ,y(-1) = e + 3
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